Question

好吧所以我需要一个输出，它告诉我同一个单词出现了多少次。我可以使用的代码或功能吗？我正在使用Grok Learning。这正是我需要的：我试图弄清楚这段代码。为此，我需要最简化的代码。这就是我的任务：

当你等着过马路时，你正在看车经过你   想知道红色或蓝色是否是汽车更受欢迎的颜色。

编写一个程序，读取每辆车的颜色字符串   开车过去，然后打印出红色汽车的数量和数量   蓝色汽车。
Cars: silver red white white blue white black green yellow silver white
red: 1 blue: 1
Cars: blue green white black silver silver silver blue silver black silver white white silver white white yellow red red silver red
red: 3 blue: 2 
Cars: yellow green white silver white blue white silver yellow pink
red: 0 blue: 1 

我目前的代码是：

    colours = []
    cars = input("Cars: ")
    colours.append(cars)
    if "red" in cars:
        for colour in colours:
          print("red:",(len(colours)))
    if "blue" in cars: 
        print("blue:",(len(colours)))

输出错误数量的单词＆＃39; red＆＃39;或者＆＃39; blue＆＃39; 请帮助：）

Answer 1

<强> ALGO

定义日期列表
从用户那里下雨天
使用set operation来获取set 2
显示没有下雨的天数。

<强>演示：

>>> day = ['monday', 'tuesday', 'wednesday', 'thursday', 'friday', 'saturday', 'sunday']
>>> rain_days = raw_input("Which days had rain (use space for saparated)? ")
Which days had rain (use space for saparated)? wednesday friday
>>> day_count_without_rain = set(day).difference(days).__len__()
>>> print day_count_without_rain
5
>>>

注意：在 Python 2.x

中使用raw_input
在 Python 3.x
中使用input
[编辑2 ]

使用列表及其计数方法

<强>演示：

>>> car_colors = raw_input("Enter string of the colour of each car that drives past") Enter string of the colour of each car that drives past red blue Red white black green # Convert to lower case. >>> car_colors = car_colors.lower() #- spit colors in to list. >>> car_colors = car_colors.split() >>> print "Red Color cars count:", car_colors.count("red") Red Color cars count: 2 >>> print "Blue Color cars count:", car_colors.count("blue") Blue Color cars count: 1 >>>

count ：这将返回整数，即搜索元素在字符串或列表中出现的次数。

<强>演示：

>>> l = [1,2,3,1, 0] >>> l.count(1) 2 >>> l.count(11) 0 >>> a = "aagghhttee" >>> a.count("a") 2 >>> a.count("aa") 1 >>> a.count("aaa") 0 >>>

Answer 2

import collections

colorCounts = collections.defaultdict(int, collections.Counter(input("cars: ").lower().split()))
needed = 'red blue'.split()
for n in needed:
    print("{}:".format(n), colorCounts[n])

Answer 3

这是最简单的解决方案，也是Grok Learning提供的示例解决方案：

cars = input('Cars: ')
cars = cars.split()

red = blue = 0
for car in cars:
  if car == 'red':
    red += 1
  elif car == 'blue':
    blue += 1

print('red:', red)
print('blue:', blue)

我希望这会有所帮助！

如何找到python中有多少单词？

3 个答案: