Question

我是XML解析的初学者当children属性符合某些条件时，我无法提取特定值。

这是我的xml文件示例（来自http://www.uniprot.org/uniprot/Q63HN8.xml）：

<uniprot xmlns="http://uniprot.org/uniprot" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://uniprot.org/uniprot http://www.uniprot.org/support/docs/uniprot.xsd">
  <entry dataset="Swiss-Prot" created="2007-02-20" modified="2015-09-16" version="112">
    <accession>Q63HN8</accession>
    <accession>C9JCP4</accession>
    <accession>D6RI12</accession>
  <dbReference type="Proteomes" id="UP000005640">
    <property type="component" value="Chromosome 17"/>
  </dbReference>
  <dbReference type="Bgee" id="Q63HN8"/>
  <dbReference type="CleanEx" id="HS_KIAA1618"/>
  <dbReference type="ExpressionAtlas" id="Q63HN8">
    <property type="expression patterns" value="baseline and differential"/>
  </dbReference>
  <dbReference type="GO" id="GO:0005737">
    <property type="term" value="C:cytoplasm"/>
    <property type="evidence" value="ECO:0000314"/>
    <property type="project" value="UniProtKB"/>
  </dbReference>
  <dbReference type="GO" id="GO:0016020">
    <property type="term" value="C:membrane"/>
    <property type="evidence" value="ECO:0000314"/>
    <property type="project" value="UniProtKB"/>
  </dbReference>
  <dbReference type="GO" id="GO:0016887">
    <property type="term" value="F:ATPase activity"/>
    <property type="evidence" value="ECO:0000314"/>
    <property type="project" value="UniProtKB"/>
  </dbReference>
  <dbReference type="GO" id="GO:0016874">
    <property type="term" value="F:ligase activity"/>
    <property type="evidence" value="ECO:0000501"/>
    <property type="project" value="UniProtKB-KW"/>
  </dbReference>

当属性属性中的“value”以“C：”开头时，我想在dbReference中提取“id”值所以预期的输出是： “GO：0005737” “GO：0016020”

到目前为止，这是我的脚本：

import urllib2
from lxml import etree

file = urllib2.urlopen('http://www.uniprot.org/uniprot/Q63HN8.xml')
tree = etree.parse(file)
root = tree.getroot()
for node in tree.iter('{http://uniprot.org/uniprot}dbReference'):
   if node.attrib.get('type') == 'GO':
        value = node.attrib.get('value');
        print value
        if value.str.startswith('C:'):
            goterm = node.attrib.get('id')
            print goterm

但它远没有工作。

修改

另外，如何将不同搜索的值存储到列表中？预期： goterm_when_C = ['GO：0005737'，'GO：0016020'，'GO：0005730'] goterm_when_F = ['GO：0016887'，'GO：0016874'，'GO：0004842'，'GO：0008270'] 当我尝试：

goterm_when_C = []
goterm_when_F = []
            if value.startswith('C:'):
                go_location = node.attrib.get('id')
                for item in go_location:
                    goterm_when_C.append(item)
            if value.startswith('F:'):
                go_function = node.attrib.get('id')
                for item in go_function:
                    goterm_when_F.append(item)
                break

我得到了

>>> goterm_when_C
['G', 'O', ':', '0', '0', '0', '5', '7', '3', '7', 'G', 'O', ':', '0', '0', '1', '6', '0', '2', '0', 'G', 'O', ':', '0', '0', '0', '5', '7', '3', '0']

非常感谢任何帮助

Answer 1

您需要遍历子节点，然后检查其属性。示例 -

for node in tree.iter('{http://uniprot.org/uniprot}dbReference'):
   if node.attrib.get('type') == 'GO':
       for child in node:
           value = child.attrib.get('value');
           print value
           if value.startswith('C:'):
               goterm = node.attrib.get('id')
               print goterm
               break

Python：当children属性符合条件时提取XML元素值

修改

1 个答案: