我用 Swift 2.0 进行编码。
我得到了这样的URL字符串:
let urlString = "http://example.com/api/getfile/?filepath=C:\\1.txt"
当我将其转换为NSURL时,它返回nil。
let OrginUrl = NSURL(string: urlString)
任何人都知道怎么做?
答案 0 :(得分:5)
有两个问题需要解决:
为了包含\
,必须对其进行转义,因为它本身就是转义字符。
'\'字符,因此需要对其进行URL编码
let urlString = "http://example.com/api/getfile/?filepath=C:\\\\1.txt"
print("urlString: \(urlString)")
var escapedString = urlString.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLHostAllowedCharacterSet())
print("escapedString!: \(escapedString!)")
let orginUrl = NSURL(string: escapedString!)
print("orginUrl: \(orginUrl!)")
urlString:
http://example.com/api/getfile/?filepath=C:\\1.txtescapedString!:
http%3A%2F%2Fexample.com%2Fapi%2Fgetfile%2F%3Ffilepath = C%3A%5C%5C1.txtorginUrl:
HTTP%3A%2F%2Fexample.com%2Fapi%2Fgetfile%2F%3Ffilepath = C%3A%5C%5C1.txt
答案 1 :(得分:2)
你应该使用unicode而不是反斜杠两次。
不推荐使用
stringByAddingPercentEscapesUsingEncoding
:改为使用stringByAddingPercentEncodingWithAllowedCharacters(_:)
,它始终使用推荐的UTF-8编码,并对特定的URL组件或子组件进行编码,因为每个URL组件或子组件对于什么都有不同的规则字符有效。
以下是示例代码:
let myLink = "http://example.com/api/getfile/?filepath=C:\u{005C}\u{005C}1.txt"
var newLink = ""
if let queryIndex = myLink.characters.indexOf("?"){
newLink += myLink.substringToIndex(queryIndex.successor())
if let filePathIndex = myLink.characters.indexOf("=")?.successor() {
newLink += myLink.substringWithRange(queryIndex.successor()...filePathIndex.predecessor())
let filePath = myLink.substringFromIndex(filePathIndex)
if let pathEscaped = filePath.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLPathAllowedCharacterSet()) {
newLink += pathEscaped
}
}
}
if let newURL = NSURL(string: newLink) {
print(newURL, separator: "", terminator: "")
} else {
print("invalid")
}
结果你会得到: