我用Lua 5.1。我想解析以下模式的XML文件。我应该怎么做呢？

时间：2015-10-01 02:31:52

标签： lua xml-parsing pattern-matching luaxml

我尝试使用LuaXml库。但它的功能是有限的，因为它只返回特定属性的第一个子表，并且不会超过它。然后我尝试了字符串模式匹配，但我达到了死胡同，它无法完全完成任务。 LuaExpat库存在于lua的lib文件夹中，还有一个名为lom.lua的文件。但通常它不起作用或给我错误＆＃34;模块未找到＆＃34;

我的XML文件如下所示：

<Service>
<NewInstance ref="5A">
<Std>DiscoveredElement</Std>
<Key>5A</Key>
<Attributes>
<Attribute name="TARGET_TYPE" value="weblogic_cluster" />
<Attribute name="DISCOVERED_NAME" value="/Farm_soa4_sys20_soa4_domain/soa4_domain/WSM4_Cluster" />
<Attribute name="BROKEN_REASON" value="0" />
<Attribute name="TARGET_NAME" value="/Farm_soa4_sys20_soa4_domain/soa4_domain/WSM4_Cluster" />
<Attribute name="EMD_URL" value="https://uxsys460.schneider.com:3872/emd/main/" />
</Attributes>
</NewInstance>

<NewInstance ref="6C">
<Std>DiscoveredElement</Std>
<Key>6C</Key>
<Attributes>
<Attribute name="TARGET_TYPE" value="oracle_weblogic_nodemanager" />
<Attribute name="SERVICE_TYPE" value=" " />
<Attribute name="ORG_ID" value="0" />
<Attribute name="TARGET_NAME" value="Oracle WebLogic NodeManager-uxlab090" />
</Attributes>
</NewInstance>

<NewInstance ref="98">
<Std>DiscoveredElement</Std>
<Key>98</Key>
<Attributes>
<Attribute name="TARGET_TYPE" value="composite" />
<Attribute name="SERVICE_TYPE" value=" " />
<Attribute name="TARGET_NAME" value="SYS-IMG-Grp" />
<Attribute name="EMD_URL" value="" />
</Attributes>
</NewInstance>

<NewRelationship>
<Parent>
<Instance ref="98" />
</Parent>
<GenericRelations>
<Relations type="contains">
<Instance ref="5A" />
</Relations>
</GenericRelations>
</NewRelationship>

<NewRelationship>
<Parent>
<Instance ref="5A" />
</Parent>
<GenericRelations>
<Relations type="contains">
<Instance ref="6C" />
</Relations>
</GenericRelations>
</NewRelationship>
<NewRelationship>
<Parent>
<Instance ref="5A" />
</Parent>
<GenericRelations>
<Relations type="contains">
<Instance ref="98" />
</Relations>
</GenericRelations>
</NewRelationship>
</Service>

我的议程是显示一个NewInstance ID及其对应的目标类型和目标名称，以及它的关系类型以及与其相关的实例ref的ID，以及它的目标类型和目标名称 例如：

NewInstance ID - 5A
Target Type - weblogic_cluster 
Target Name - /Farm_soa4_sys20_soa4_domain/soa4_domain/WSM4_Cluster
Relation Type - contains
Instance ref - 6C
Target Type - oracle_weblogic_nodemanager
Target Name - Oracle WebLogic NodeManager-uxlab090
Instance ref - 98
Target Type - composite
Target Name - SYS-IMG-Grp

现在LuaXml无法用来实现这一点。字符串模式匹配的代码我将在下面列出，它可以帮助我完成任务直到关系类型但不准确

代码是：

a={}
b={}
c={}
d={}
p=0
i=0
q=0

local file = io.open("oem_topology_output.xml", "rb")   -- Open file   for    reading (binary data)
  for instance in file:read("*a"):gmatch("<NewInstance ref=\"(.-)\">") do
     a[i] = instance
     i = i+1
  end
file:close()
local files = io.open("oem_topology_output.xml", "rb")   -- Open file for  reading (binary data)
  for instances in files:read("*a"):gmatch("<NewInstance ref=\".-\">(.-)</NewInstance>") do
     TARGET_TYPE = instances:match('TARGET_TYPE.-value="(.-)"')
     TARGET_NAME = instances:match('TARGET_NAME.-value="(.-)"')
     b[p] = TARGET_TYPE
     c[p] = TARGET_NAME
     p =p+1
  end
local file = io.open("oem_topology_output.xml", "rb")   -- Open file   for   reading (binary data)
  for type in file:read("*a"):gmatch("<Relations type=\"(.-)\">") do
    d[q] = type
    q = q+1
  end
files:close()
for j=0,i-1 do
print("INSTANCE ID : ", a[j])
print("TARGET TYPE : ", b[j])
print("TARGET NAME : ", c[j])
print("RELATION TYPE : ",d[j])
end

请建议我应该遵循哪种方法才能以所需方式解析XMl文件。哪个内置库将提供apt功能。如果你建议，LuaExpat让我知道它为什么不适合我的可能原因。

2 个答案:

答案 0 :(得分：1)

你不需要任何特殊的库来解析lua中的xml，有很多内置的功能来编写你自己的解析器。

例如，要检索节点的属性，您可以编写类似这样的内容。

local file = "oem_topology_output.xml"
local node = "<(%a-)%s* "
local attributes = {
    "ref",
    "name",
    "value",
    "type"
}


for line in io.lines(file) do
    for a in line:gmatch(node) do
        for x = 1, #attributes do
            n = line:match(attributes[x]..'="(.-)"')
            if n then
                print(a, attributes[x], n)
            end
        end
    end
end

产生类似

的输出 
NewInstance ref 5A
Attribute   name    TARGET_TYPE
Attribute   value   weblogic_cluster
Attribute   name    DISCOVERED_NAME
Attribute   value   /Farm_soa4_sys20_soa4_domain/soa4_domain/WSM4_Cluster
Attribute   name    BROKEN_REASON
Attribute   value   0
Attribute   name    TARGET_NAME
Attribute   value   /Farm_soa4_sys20_soa4_domain/soa4_domain/WSM4_Cluster
Attribute   name    EMD_URL
Attribute   value   https://uxsys460.schneider.com:3872/emd/main/
NewInstance ref 6C
Attribute   name    TARGET_TYPE
Attribute   value   oracle_weblogic_nodemanager
Attribute   name    SERVICE_TYPE
Attribute   value    
Attribute   name    ORG_ID
Attribute   value   0
Attribute   name    TARGET_NAME
Attribute   value   Oracle WebLogic NodeManager-uxlab090
NewInstance ref 98
Attribute   name    TARGET_TYPE
Attribute   value   composite
Attribute   name    SERVICE_TYPE
Attribute   value    
Attribute   name    TARGET_NAME
Attribute   value   SYS-IMG-Grp
Attribute   name    EMD_URL
Attribute   value   
Instance    ref 98
Relations   type    contains
Instance    ref 5A
Instance    ref 5A
Relations   type    contains
Instance    ref 6C
Instance    ref 5A
Relations   type    contains
Instance    ref 98

无需打开或关闭文件，因为无意写入文件。

答案 1 :(得分：0)

local a, b, c, d = {}, {}, {}, {}

local h = io.open("oem_topology_output.xml", "rb")   
if not h then return end
local txt = h:read("*a")
h:close()

for ref, instances in txt:gmatch('<NewInstance ref="(%w+)">(.-)</NewInstance>') do
    a[#a+1] = ref   
    TARGET_TYPE = instances:match('name="TARGET_TYPE"%s+value="(.-)"')
    if TARGET_TYPE then b[#b+1] = TARGET_TYPE end
    TARGET_NAME = instances:match('name="TARGET_NAME"%s+value="(.-)"')
    if TARGET_NAME then  c[#c+1] = TARGET_NAME end
end

for relationship in txt:gmatch('<NewRelationship>(.-)</NewRelationship>') do
    parent = relationship:match('<Parent>.-ref="(%w+)".-</Parent>')
    node = relationship:match('<Relations type="contains">.-ref="(%w+)".-</Relations>')
    if parent and node then    d[#d+1] = {  [parent] = node } end
end

for j=1,#a do
   local id = a[j]
    print("INSTANCE ID : ", id)
    print("TARGET TYPE : ", b[j])
    print("TARGET NAME : ", c[j])
    for k,v in  pairs(d) do
        if type(v)=='table' and v[id] then
            print("\tRELATION: ",v[id])
        end
    end
end

输出：

INSTANCE ID :   5A
TARGET TYPE :   weblogic_cluster
TARGET NAME :   /Farm_soa4_sys20_soa4_domain/soa4_domain/WSM4_Cluster
    RELATION:   6C
    RELATION:   98
INSTANCE ID :   6C
TARGET TYPE :   oracle_weblogic_nodemanager
TARGET NAME :   Oracle WebLogic NodeManager-uxlab090
INSTANCE ID :   98
TARGET TYPE :   composite
TARGET NAME :   SYS-IMG-Grp
    RELATION:   5A
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