Question

I'm trying to Write the main method of a Java program that has the user enter two integers, i and n. If either integer is less than 2, output “Please enter numbers above 1.” Otherwise, output the n positive multiples of i, separated by spaces.

I'm close but can't figure out how to do display the multiples.

Here's what a sample run should look like:

Enter i: 4

Enter n: 6

6 multiples of 4 are: 8 12 16 20 24 28

import java.util.*;
public class HW5Problem3 {
   public static void main (String [] args) {

      int i = 0;
      int n = 0;

      Scanner input = new Scanner(System.in);

         System.out.print("Enter i: ");
         i = input.nextInt();
         System.out.print("Enter n: ");
         n = input.nextInt();

         if ((i <= 1) || (n <= 1)) {
            System.out.println("Please enter numbers above 1");
            System.exit(1);
         }

         System.out.print(n + " multiples of " + i + " are: ");

   }
}

Answer 1

你需要创建一个循环（for循环或while循环）从2迭代到n + 1，并将i乘以你的循环变量，输出循环中的每个值

Answer 2

n是乘数，i是因素，对吗？在编程中，乘数是循环最大值：

System.out.print(n + " multiples of " + i + " are: ");
for (int inc=1; inc<=n; inc++) {
    System.out.print(" " + i*inc);
}

打印出来：4 8 12 16 20 24

如果你真的想把它作为输出：8 12 16 20 24 28复制/粘贴这一行：

for (int inc=2; inc<=(n+1); inc++)

Answer 3

你可以在那个班级中使用以下方法

   public static void mult(int i,int n){
   int[] arr=new int[n];
   int count=2;
   for(int x=0;x<n;x++){
       arr[x]=i*count++;
   }
   for(int y=0;y<arr.length;y++){
   System.out.print(arr[y]+" ");

}

现在您的最终代码看起来像

import java.util.*;

public class HW5Problem3 {
    private int i = 0;
    private int n = 0;

    public static void main(String[] args) {

        int i = 0;
        int n = 0;

        Scanner input = new Scanner(System.in);

        System.out.print("Enter i: ");
        i = input.nextInt();
        System.out.print("Enter n: ");
        n = input.nextInt();

        if ((i <= 1) || (n <= 1)) {
            System.out.println("Please enter numbers above 1");
            System.exit(1);
        } else {
            System.out.print(n + " multiples of " + i + " are: ");
            mult(i, n);
        }

    }

    public static void mult(int i, int n) {
        int[] arr = new int[n];
        int count = 2;
        for (int x = 0; x < n; x++) {
            arr[x] = i * count++;
        }
        for (int y = 0; y < arr.length; y++) {
            System.out.print(arr[y] + " ");
        }
    }
}

Answer 4

//fills matrix with matlab like syntax
macro_rules! mat {
    [] => { MatrixXf::construct(Vec::new(), 0, 0) };
    [ $( $x: expr ),* $(; $( $y: expr ),*)* ] => {{
        let mut tmp_vec = Vec::new();
        let mut rows = 0;
        let mut inner_cols = 0;
        $(
            tmp_vec.push($x);
            inner_cols += 1;
        )*
        let cols = inner_cols; // remember how many columns the first row has
        rows += 1;
        $(
            inner_cols = 0;
            $(
                tmp_vec.push($y);
                inner_cols += 1;
            )*
            assert!(inner_cols == cols); // check that the following rows have as many columns as the first row
            rows += 1;
        )*
        MatrixXf::construct(tmp_vec, rows, cols)//fills MatrixXf fields
    }}
}

Create a java program to display multiples of a number

4 个答案: