问题是如何根据最大值和最小值按键提取值解析字典。然后比较其中的值，并根据计算添加一些键值。也许问题很混乱，但我会用代码提供更多解释。
[
{
"YCI": 0.014076729909151329,
"TCI": 0.5610661498232027,
"FCI": 0.327632092582722,
"TFCI": 3.04906430661623,
"naziv": "HDZ",
"YCSI": 14.49723089452966
},
{
"YCI": 0.04249999676677044,
"TCI": 0.33129318126147167,
"FCI": 1.677073944380761,
"TFCI": 4.326953034001479,
"naziv": "HNS",
"YCSI": 56.80909574468085
},
{
"YCI": 0,
"TCI": 0.40603351151808614,
"FCI": 0,
"TFCI": 12.61045547126369,
"naziv": "HSP AS",
"YCSI": 0
},
{
"YCI": 2.231205214448367,
"TCI": 0,
"FCI": 0,
"TFCI": 0,
"naziv": "HSS",
"YCSI": 949.343111111111
}
]
好的，这是我的字典。现在如何比较字典中的键：
彼此根据他们的价值观。如果值YCI具有最高值然后是YCI，则它应该在新字典中设置数字1，并且该逻辑也应用于字典中的其他键。 输出将类似于：
[
{
"YCI": 3,
"TCI": 1,
"FCI": 2,
"TFCI": 3,
"naziv": "HDZ",
"YCSI": 3
},
{
"YCI": 2,
"TCI": 3,
"FCI": 1,
"TFCI": 2,
"naziv": "HNS",
"YCSI": 2
},
{
"YCI": 0,
"TCI": 2,
"FCI": 0,
"TFCI": 1,
"naziv": "HSP AS",
"YCSI": 0
},
{
"YCI": 1,
"TCI": 0,
"FCI": 0,
"TFCI": 0,
"naziv": "HSS",
"YCSI": 1
}
]
最高值得到数字1，最低值取决于字典包含的对象数量。
print max(nvalues[0].iteritems(), key=operator.itemgetter(1))[1]
使用此代码，我可以提取最高值，但如何在其值中对字典进行排序。如果你能给我一些逻辑来解决这个问题，我将不胜感激。
答案 0 :(得分：1)
def rank_by_value(list_dicts):
from operator import itemgetter
from itertools import groupby
nums = []
symbs = []
# separting keys, values into two lists
# one for numeric values, the other for string values
for indx, d in enumerate(list_dicts):
for k, val in d.items():
if type(val) in (int,float):
nums.append((indx,k,val))
else:
symbs.append((indx,{k:val}))
groups = []
# grouping lists
for k, g in groupby(nums, key=itemgetter(0)):
groups.append(list(g))
allData = []
# sorting lists by by each dictionry values and assinging ranks
for g in groups:
sort_ed = sorted(g, key=itemgetter(2), reverse=True)
ranked = [ list((t,i+1)) for i,t in enumerate(sort_ed)]
allData.append(ranked)
ranked = []
# remove numerical data
for zero in allData:
for i, el in enumerate(zero):
one,two, _ = el[0]
zero[i] = one,(two, el[1])
# now creating dictionaries anew
list_of_dict = []
dict_temp = {}
for i, (el, sy) in enumerate(zip(allData, symbs)) :
for l in el:
name_, rank_ = l[1]
dict_temp[name_] = rank_
dict_temp.update(symbs[i][1])
list_of_dict.append(dict_temp)
dict_temp = {}
return list_of_dict
for el in rank_by_value(jsn):
print(el)
{'TCI': 3, 'YCSI': 1, 'naziv': 'HDZ', 'YCI': 5, 'FCI': 4, 'TFCI': 2}
{'TCI': 4, 'YCSI': 1, 'naziv': 'HNS', 'YCI': 5, 'FCI': 3, 'TFCI': 2}
{'TCI': 2, 'YCSI': 3, 'naziv': 'HSP AS', 'YCI': 4, 'FCI': 5, 'TFCI': 1}
{'TCI': 3, 'YCSI': 1, 'naziv': 'HSS', 'YCI': 2, 'FCI': 4, 'TFCI': 5}
答案 1 :(得分：0)
import six
raw_object = [
{
"YCI": 0.014076729909151329,
"TCI": 0.5610661498232027,
"FCI": 0.327632092582722,
"TFCI": 3.04906430661623,
"naziv": "HDZ",
"YCSI": 14.49723089452966
},
{
"YCI": 0.04249999676677044,
"TCI": 0.33129318126147167,
"FCI": 1.677073944380761,
"TFCI": 4.326953034001479,
"naziv": "HNS",
"YCSI": 56.80909574468085
},
{
"YCI": 0,
"TCI": 0.40603351151808614,
"FCI": 0,
"TFCI": 12.61045547126369,
"naziv": "HSP AS",
"YCSI": 0
},
{
"YCI": 2.231205214448367,
"TCI": 0,
"FCI": 0,
"TFCI": 0,
"naziv": "HSS",
"YCSI": 949.343111111111
}
]
#make a list (equal in length to original object) of empty dictionaries
ranks_object = [{} for i in raw_object]
#iterate through each key in the first dictionary
#(I assumed that all dictionaries will have the same keys)
for key in raw_object[0]:
#create a list with the value for this key from all dictionaries
raw_list = [group[key] for group in raw_object]
#sort and store the list
sorted_raw_list = sorted(raw_list)
#create a list of the ranks of each of the raw values
#if the value is greater than zero, a value's rank is the length
# of the raw list minus the index of the value in the sorted list
#otherwise, the rank should be 0 (as indicated by OP's desired output)
ranks = [len(raw_list) - sorted_raw_list.index(value) if value > 0 else 0 for value in raw_list]
#iterate through each rank in the ranks list (with access to the
# list index, which will be used to make sure that the rank is
# inserted into the proper dictionary)
for index, rank in enumerate(ranks):
#if the value for the key in the first dictionary is a string,
# insert the original value with the key
#(I assumed that if one dictionary has a string value for a
# certain key, all of the dictionaries do as well)
if isinstance(raw_object[0][key], six.string_types):
ranks_object[index][key] = raw_object[index][key]
#otherwise insert the rank with the key
else:
ranks_object[index][key] = rank
#display each rank dictionary separately to improve readability
for x in ranks_object:
print x