Question

void Print(Node *head)
{

    if (head = NULL)
    {
        cout << "NULL";
    }
    else
    {
        cout << head->data << endl;
        head = head->next;
        while (head->next != NULL)
        {
            cout << head->data << endl;
            head = head->next;
        }
        cout << "NULL";
    }
}

Answer 1

我看到的一个问题是你为头

分配了NULL

if (head = NULL)必须为if (head == NULL)

Answer 2

我将假设该行

if ( head = NULL )

在转录代码时出错，而且您的工作代码使用

if ( head == NULL )

我看到的真正错误是你正在使用

    cout << head->data << endl;
    head = head->next;
    while (head->next != NULL)  // This line is not good
    {
        cout << head->data << endl;
        head = head->next;
    }
    cout << "NULL";

该行始终是个问题。在某些时候，head将等于NULL，您将尝试访问NULL指针。

将该代码块更改为：

while (head != NULL)
{
    cout << head->data << endl;
    head = head->next;
}
cout << "NULL";

实际上，整个功能可以是：

void Print(Node* head)
{
    while (head != NULL)
    {
        cout << head->data << endl;
        head = head->next;
    }
    cout << "NULL";
}

C ++打印链表，分段错误

2 个答案: