Question

我有图像，必须为每张图片计算facebook份额。我无法为此做出循环。现在只有一个元素。怎么做？我的代码是：

        <script>
        $(document).ready(function(){
        	var current = 0;
        	$count = $('#count_bombs').val();
        	$('#' + current).each(function() {
        		var id = $('#' + current).val(); console.log(id);
        		$.getJSON('https://graph.facebook.com/http://example.com/images/view/' + id, function(data) { 
        		   document.getElementById("shares_count_" +current).innerHTML = data.shares;
        		  console.log(data.shares);  console.log("#shares_count_" +current);
        		});
        		current++;
        	});

        });
        </script>

        <?php $num=0;  $id = 0; ?> 
        		<?php foreach($images as $key=>$val){  ?>
        <div>
        <a href="https://www.facebook.com/sharer/sharer.php?u=<?php echo URL::base();?>images/view/<?php echo $val['image_name'];?>">
        <span aria-hidden="true"  class="glyphicon glyphicon-link"></span>
        	<input type="hidden" id="<?php echo $id; ?>" class="count" value="<?php echo $val['image_name'];?>">
        	SHARE	
        </a>
         </div>

        <div>
       <span class="glyphicon glyphicon-comment" aria-hidden="true" ></span> 
        	<span id="shares_count_<?php echo $id; ?>"></span>
        	<input type="hidden" value="<?php echo count($bombs);?>" id="count_bombs" name="count_bombs">
       </div>

编辑：我做到了。我使用了每种方法的index参数。这是我的代码：

<script>
$(document).ready(function(){
	var current = 0;
	$("input[type=hidden]").each(function(index, element){
		var id = $('#' + current).val();
		$.getJSON('https://graph.facebook.com/http://pbombd.dev/bombs/view/' + id, function(data) { 
		   $('#shares_count_' + index).html(data.shares);
		});
		current++;
	});

});
</script>

Answer 1

count将只返回一个元素，因此无法循环。您似乎希望在页面中找到css类$('input.count').each(function() { $input = $(this); // $input contains the hidden input console.log($input.attr('id)); });的每个隐藏输入。你可以这样做：

{{1}}

如何循环遍历jQuery的所有元素

1 个答案: