当我使用Junit的org.junit.rules.Timeout和spring的基类AbstractTransactionalJUnit4SpringContextTests时,我得到了这个例外:
org.springframework.dao.InvalidDataAccessApiUsageException: no transaction is in progress; nested exception is javax.persistence.TransactionRequiredException: no transaction is in progress
日志输出显示:
2010-07-20 09:20:16 INFO [TransactionalTestExecutionListener.startNewTransaction] Began transaction (1): transaction manager [org.springframework.orm.jpa.JpaTransactionManager@6a1fbe]; rollback [true]
2010-07-20 09:20:16 INFO [TransactionalTestExecutionListener.endTransaction] Rolled back transaction after test execution for test context [[TestContext@17b60b6 testClass = MyIntegrationTest, locations = array<String>['classpath:/context.xml', 'classpath:/junit-context.xml'], testInstance = MyIntegrationTest@10a4d7c, testMethod = myTest@MyIntegrationTest, testException = org.springframework.dao.InvalidDataAccessApiUsageException: no transaction is in progress; nested exception is javax.persistence.TransactionRequiredException: no transaction is in progress]]
这是我的测试:
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = {"classpath:/context.xml", "classpath:/junit-context.xml"})
@TransactionConfiguration(transactionManager = "transactionManager", defaultRollback = true)
@Transactional
public class MyIntegrationTest extends AbstractTransactionalJUnit4SpringContextTests{
@Rule public Timeout globalTimeout = new Timeout(30000);
@Test
public void myTest() {
// transactional code here saving to the database...
}
}
然而,每当我评论出规则时,一切正常。
我如何将这两者结合起来才能正常工作?
答案 0 :(得分:0)
啊,我把它解决了。我解决它的方法是以编程方式设置事务。
@Autowired TransactionManager transactionManager;
@Test
public void test() {
TransactionTemplate transactionTemplate = new TransactionTemplate(transactionManager);
transactionTemplate.execute(new TransactionCallbackWithoutResult() {
@Override
protected void doInTransactionWithoutResult(TransactionStatus status) {
status.setRollbackOnly();
// DO YOUR TEST LOGIC HERE
}
});
}
希望它有所帮助。
答案 1 :(得分:0)
LOL。
您也可以简单地使用@Transactional(timeout = 30)注释您的测试方法30秒超时。哪个更简单。