Question

我想将文本字符串中的所有URL出现为链接。我试过的时候

preg_match($reg_exUrl, $text, $url) echo preg_replace($reg_exUrl1, '<a href="'.$url[0].'" rel="nofollow">'.$url[0].'</a>', $text);

它已取代所有地方的第一个匹配网址。

此外，正则表达式无法检测以www。

开头的URL

$reg_exUrl1 = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";

$text = "The text you want to filter goes here. http://www.google.com data which in the http://www.apple.com";

if( preg_match($reg_exUrl, $text, $url)){
 echo preg_replace($reg_exUrl1, '<a href="'.$url[0].'" rel="nofollow">'.$url[0].'</a>', $text);
   // if no URLs in the text just return the text

}else {
    echo "IN Else #$".$text;
 }

这是字符串中＃值检测的代码。

$ text =“这是对文本中#tag值的检测。任何带#hash的#special值都将显示为链接”;

$reg_exUrl ="/#\w+/";
if( preg_match($reg_exUrl1, $text, $url)){
    echo preg_replace($reg_exUrl1, '<a href="'.$url[0].'"     rel="nofollow">'.$url[0].'</a>', $text);
}else {
  echo "not Matched".$text;

}

Answer 1

检查

$reg_exUrl1 = "~(http|https|ftp|ftps)://[a-zA-Z0-9-.]+\.[a-zA-Z]{2,3}(/S*)?~";

$text = "The text you want to filter goes here. http://www.google.com data which in the http://www.apple.com";

if( preg_match($reg_exUrl1, $text, $url)){
 echo preg_replace($reg_exUrl1, '<a href="$0" rel="nofollow">$0</a>', $text);
   // if no URLs in the text just return the text

}else {
    echo "IN Else #$".$text;
 }

更新

$reg_exUrl ="/#\w+/";
if( preg_match($reg_exUrl, $text, $url)){
   echo preg_replace($reg_exUrl, '<a href="$0" rel="nofollow">$0</a>', $text);
}else {
  echo "not Matched".$text;

用于url的php正则表达式操作和＃值检测

1 个答案: