如何按层次排序行

时间:2015-09-30 05:55:02

标签: sql sql-server tsql

我有一个具有分层,父子关系的表,并希望按该层次结构对其进行排序。表是:

id|parent|type
--------------
1 |0     |1
2 |0     |1
3 |0     |1
4 |0     |2
5 |0     |2
6 |2     |2
7 |3     |2

结果我想要这个:

id|parent|type
--------------
1 |0     |1
2 |0     |1
6 |2     |2
3 |0     |1
7 |3     |2
4 |0     |2
5 |0     |2

所以我希望获得类似树形视图的东西,其中类型1首先排序,最后输入2。

现在我尝试使用递归,但顺序错误:

with cte as
(
  select id, parent, type from tbl where id=1
  union all
  select id, parent, type,
  ROW_NUMBER()over(
   order by
         (case when t.type = 1 then 1
            when t.type = 2 then 2
    else 1000
    end) as rn
  from tbl t
  inner join cte c on c.id=t.parent
)
select * from cte
order by rn

我该怎么做?

3 个答案:

答案 0 :(得分:3)

可以使用以下递归CTE完成:

WITH cte AS (
  SELECT *,
    CAST(ROW_NUMBER() OVER(ORDER BY id) AS REAL) rn,
    1 level
  FROM tbl
  WHERE parent = 0
  UNION ALL
  SELECT t2.*,
    cte.rn + (CAST(ROW_NUMBER() OVER(ORDER BY t2.id) AS REAL) / POWER(10, cte.level)) rn,
    cte.level + 1 level
  FROM tbl t2 INNER JOIN cte
    ON t2.parent = cte.id
)
SELECT id, parent, type
FROM cte
ORDER BY rn

请参阅SQLFiddle更复杂的示例数据(更深层次结构,"无序的父子ID' s")

答案 1 :(得分:1)

使用带有cte的hierarchyid顺序很简单,不测试递归关系

DECLARE @Data table (Id int identity(1,1) primary key, Parent int, Type int)

INSERT @Data VALUES 
(0, 1),
(0, 1),
(0, 1),
(0, 2),
(0, 2),
(2, 2),
(3, 2)

SELECT * FROM @Data

;WITH level AS
(
    -- The root, build the hierarchy by /{Type}.{Id}/, where Type is important then Id
    SELECT *, -- 0 AS Level,
        '/' + CONVERT(varchar(max), Type + 0.1 * Id) + '/' AS Ordering 
    FROM @Data 
    WHERE Parent = 0
    UNION ALL
    -- Connect the parent with appending the hierarchy
    SELECT d.*, -- c.Level + 1, 
        c.Ordering + CONVERT(varchar(max), d.Type + 0.1 * d.Id) + '/' 
    FROM @Data d INNER JOIN level c ON d.Parent = c.Id
)
SELECT Id, Parent, Type FROM level 
ORDER BY CAST(Ordering as hierarchyid) -- The key part to convert data type

SQL Fiddle

答案 2 :(得分:0)

with cte as
(
  select *, 1 level, row_number() over (order by id) rn
  from tbl
  where parent = 0
  union all
  select t.*, cte.level + 1 level, cte.rn
  from cte
  inner join tbl t on cte.id = t.parent
)
select id, parent, type from cte order by rn, level