Question

让我们去点，

我有一个像这样的表格

exhibition.php

<?php
    include("email_class.php");
if(isset($_POST[SAVE])){

   $email = $_POST[EMAIL];
   $company = $_POST[COMPANY];
   $gender  = $_POST[GENDER];
   $buyer   = $_POST[BUYER];
 $discussion = $_POST[DISCUSSION]; 

   $class = new email_class();

    $class->notifikasi($discussion);



}//end if
 ?>

代码包含这样的文件

email_class.php

<?php

class email_class{

   function notifikasi($discussion){

       if($discussion == "DISCUSSION"){


        $to  = $email;      
        $subjek = "Thanks for visiting us at Gulfood exhibition, Dubai";
        $message = "<html>
        <head>
            <title>Exibithion Email</title>
        </head>


        <body>
          bla blaa";

$message.= "Dear <b> ".$gender." ".$buyer."</b><br><br>";

$headers  = "MIME-Version: 1.0" . "\r\n";

    $headers .= "Content-type:text/html;charset=UTF-8" . "\r\n";

    $headers .= 'From: **** Group <export@***>' . "\r\n";

echo $message;

     }//end if    





   }//end function


}//end of class



?>

好的，回复HTML邮件是Succees。任何事情都运行良好，只有来自exhibition.php的变量不能传递给email_class.php。

任何人都可以解决我的问题吗？

Answer 1

将值作为参数传递给notifikasi。

 <?php
     include("email_class.php");
     if(isset($_POST[SAVE])){

           $class = new email_class();

           $class->notifikasi($_POST[EMAIL], $_POST[COMPANY], $_POST[GENDER], $_POST[BUYER], $_POST[DISCUSSION])

    }//end if
 ?>

上课

class email_class{

   function notifikasi($email, $company, $gender, $buyer, $discussion){

       if($discussion == "DISCUSSION"){
 /** ... **/

PHP Cant Pass变量包含文件？

1 个答案: