Question

我是laravel的新手并使用laravel5。这是我的控制器：

public function store(Request $request)
{
    $image=$request->all();
    if($request->hasFile('image')) {
        $file = $request->file('image');
        $name = $file->getClientOriginalName();
        $image->filePath = $name;
        $file->move(public_path().'/images/', $name);
        Image::create($image);
    }      
    return redirect()->back();
}

这是我的表格：

{!! Form::text('title') !!}
{!! Form::text('description')!!}
{!! Form::file('image') !!}
{!! Form::submit('Save') !!}

在上传时获取错误“尝试分配非对象的属性”。提前致谢

Answer 1

将您的代码更改为以下内容：

public function store(Request $request)
{
    $image=$request->all();
    if($request->hasFile('image')) {
        $file = $request->file('image');
        $name = $file->getClientOriginalName();
        $image['image'] = $name; // This line has changed
        $file->move(public_path().'/images/', $name);
        Image::create($image);
    }      
    return redirect()->back();
}

Answer 2

它应该是这样的：

public function store(Request $request) {
    $image=$request->all();
    if($request->hasFile('image')) {
        $file = $request->file('image');
        $name = $file->getClientOriginalName();
        $image['image'] = $name;
        $file->move(base_path().'/images/', $name);    
    }      
    Image::create($image);
    return redirect()->back();
}

Answer 3

问题是 $ image 是请求即时之一。而且您正在尝试获取一个不存在的请求对象表单。

您需要对代码进行一些更改，这应该适合您

public function store(Request $request)
{
    $image = $request->all();

    if($request->hasFile('image')) {
        $file = $request->file('image');

        //you also need to keep file extension as well
        $name = $file->getClientOriginalName().'.'.$file->getClientOriginalExtension();

        //using array instead of object
        $image['filePath'] = $name;
        $file->move(public_path().'/images/', $name);

        Image::create($image);

    }      
    return redirect()->back();
}

Laravel 5图片上传问题

3 个答案: