Question

2正则表达式问题

如何匹配子模式（）中的单词或2个单词？

我如何匹配一个单词或两个单词，后跟一个特定单词，如“with”或字符串结尾$

我试过

(\w+\W*\w*\b)(\W*\bwith\b|$)

但它肯定无法正常工作

编辑：我正在考虑将“go to mall”和“go to”相匹配，这样我就可以在python中组合“go to”。

Answer 1

也许是这样的？

>>> import re
>>> r = re.compile(r'(\w+(\W+\w+)?)(\W+with\b|\Z)')
>>> r.search('bar baz baf bag').group(1)
'baf bag'
>>> r.search('bar baz baf with bag').group(1)
'baz baf'
>>> r.search('bar baz baf without bag').group(1)
'without bag'
>>> r.search('bar with bag').group(1)
'bar'
>>> r.search('bar with baz baf with bag').group(1)
'bar'

Answer 2

以下是我提出的建议：

import re


class Bunch(object):
    def __init__(self, **kwargs):
        self.__dict__.update(kwargs)


match = re.compile(
    flags = re.VERBOSE,
    pattern = r"""
        ( (?!with) (?P<first> [a-zA-Z_]+ ) )
        ( \s+ (?!with) (?P<second> [a-zA-Z_]+ ) )? 
        ( \s+ (?P<awith> with ) )? 
        (?![a-zA-Z_\s]+)
        | (?P<error> .* )
    """
).match

s = 'john doe with'

b = Bunch(**match(s).groupdict())

print 's:', s

if b.error:
    print 'error:', b.error
else:
    print 'first:', b.first
    print 'second:', b.second
    print 'with:', b.awith

Output:
s: john doe with
first: john
second: doe
with: with

还尝试了：

s: john
first: john
second: None
with: None

s: john doe
first: john
second: doe
with: None

s: john with
first: john
second: None
with: with

s: john doe width
error: john doe width

s: with
error: with

BTW：re.VERBOSE和re.DEBUG是你的朋友。

此致米克。

正则表达式匹配单词和字符串结尾

2 个答案: