Nhibernate无法使用Oracle数据库从HiLo表读取。 （无法从表中读取hi值）这是已知错误吗？

Question

设定：

• Oracle 11g企业版11.2.0.1.0版64位生产
• Toad For Oracle 12.1.0.22
• Nhibernate 4.0.0.4000
• Fluent Nhibernate 2.0.1.0
• 根据C＃4.5.1开发项目

流利配置：

var configuration = Fluently.Configure()
                    .Database(OracleManageDataClientConfiguration.Oracle10
                        .ConnectionString("my-connection-string")
                        .IsolationLevel(IsolationLevel.ReadCommitted).ShowSql())
                    .Mappings(x => x.FluentMappings.AddFromAssembly(my-assembly)
                        .Convention.Add<CustomIdentityHiloConvetion>())
                    .ExposeConfiguration(buildSchema)
                    .BuildConfiguration();

流利公约：

public class CustomIdentityHiloConvetion : IIdConvention
{
    public void Apply(IIdentityInstance instance)
    {
        instance.GeneratedBy.HiLo("NEXTHIVALUETABLE", "NEXTHIVALUECOLUMN", 10, builder => 
            builder.AddParam("where", string.Format("{0} = '{1}'", "TABLENAME", instance.EntityType.Name.ToUpperInvariant())));
    }
}

来自Nhibernate的生成的SQL语句： 从NEXTHIVALUETABLE中选择NEXTHIVALUECOLUMN，其中TABLENAME ='MYSAMPLETABLE'用于更新

它抛出错误，它无法使用该语句从表NEXTHIVALUETABLE读取hi值。我直接在Toad中执行上述语句并运行完美且SQLite表。

我使用来自Nhibernate.Id命名空间的TableGenerator类（第193行）中的command.ExecuteReader语句反汇编（使用resharper）Nhibernate程序集返回no记录，因此它抛出此异常。

DoWorkInCurrentTransaction方法的快速代码：

do
{
    IDbCommand command = conn.CreateCommand();
    IDataReader rs = (IDataReader) null;
    command.CommandText = this.query; // select NEXTHIVALUECOLUMN from NEXTHIVALUETABLE where TABLENAME = 'MYSAMPLETABLE' for update
    command.CommandType = CommandType.Text;
    command.Transaction - transaction;
    PersistentIdGeneratorParmsNames.SqlStatementLogger.LogCommand("Reading high value: ", command, FormatStyle.Basic);

    try
    {
        rs = command.ExecuteReader();
        if(!rs.Read())
        {
            string message = !string.IsNullOrEmpty(this.whereClause) ? string.Format("could not read a hi value from table '{0}' using the where class ({1})- you need to populate the table"....//more statements);
            TableGenerator.log.Error((object)message);
            throw new IdentifierGeneratorException(message);
        }

        num1 = Convert.ToInt64(this.columnType.Get(rs, 0));
    }
    catch(Exception ex)
    {
        //more statements
    }
    //more statements
    ...
    ...
    ...     
}

Answer 1

instance.GeneratedBy.HiLo("NEXTHIVALUETABLE", "NEXTHIVALUECOLUMN", 10, builder => 
            builder.AddParam("WHERE", string.Format("{0} = '{1}'", "TABLENAME", instance.EntityType.Name.ToUpperInvariant())));

我为WHERE制作大写，它解决了问题。非常奇怪的问题。