Rails:既给出了块arg又给出了实际块

时间:2015-09-29 02:55:47

标签: ruby-on-rails lambda scope

我正在尝试在Rails 4中创建一个应用程序。

我在个人资料展示页面中有此代码,以显示用户创建的所有项目。

<div class="row">
      <div class="col-md-10 col-md-offset-1">
      <% Project.all_current_for_creator(@creator).sort_by(&:created_at) do |project| %>
      <div class="row">
            <div class="col-md-4">
              <div class="indexdisplay">
                <%= image_tag project.hero_image_url, width: '100%', height: '200px' if project.hero_image.present? %>
              </div>
            </div>
            <div class="col-md-8">
              <div class="row">
                <div class="col-md-12">
                  <div class="indexheading"> <%= link_to project.title, project %> </div>
                </div>
              </div>
              <div class="row">
                <div class="col-md-12">
                  <div class="indexsubtext">    
                    <%= truncate(project.description, :ommission => "...", :length => 250) %>
                  </div>              
                </div>
              </div>
            </div>
      </div>

     <% end %>

当我尝试这个时,我收到的错误是:

SyntaxError at /profiles/3
both block arg and actual block given

任何人都可以看到错误吗?

方法&#39; all_current_for_creator&#39;在我的project.rb中定义为:

def self.all_current_for_creator(creator)
    if creator.profile.present?
       creator.current.visible
    else
      guest_visible
    end
  end 

我在project.rb中定义了三个范围:

scope :creator, lambda { where(@creator_profile = user.profile_id)}

  scope :current, lambda { where('project.start_date >= ?', Date.today)}
  scope :visible, lambda { joins(:sweep => :disclosure).where('disclosures.allusers' => 'true')
    .joins(:sweep => :finalise).where('finalises.draft' => 'false') }

1 个答案:

答案 0 :(得分:2)

.sort_by(&:created_at) do |project|

应该是:

.sort_by(&:created_at).each do |project|

因为在第一种情况下,您传递了两个块&:created_atdo ...