Question

我已经写了两张桌子。第一个是名为time_dimension的一年中的所有日期，第二个名为tbl_holidays的日期是今年的公共假日。但是，我想在没有周末和假期的情况下度过这一天。我写的查询就像;

SELECT ti.id, ti.db_date, ti.year, ti.month, ti.day, ti.quarter, ti.week,   ti.day_name, ti.month_name
FROM time_dimension ti
LEFT JOIN  tbl_holidays tb on ti.db_date=tb.startdate
where  day_name in ('Monday','Tuesday','Wednesday','Thursday','Friday');

任何人都可以帮我摆脱这个查询中的假期表吗？

更新答案：

SELECT ti.id, ti.db_date, ti.year, ti.month, ti.day, ti.quarter, ti.week, ti.day_name, ti.month_name
FROM DeJuMa.time_dimension ti
LEFT JOIN  tbl_holidays tb on ti.db_date=tb.startdate
where  day_name in ('Monday','Tuesday','Wednesday','Thursday','Friday')
AND ti.db_date NOT IN (select startdate from tbl_holidays tb );

Answer 1

    SELECT ti.id, ti.db_date, ti.year, ti.month, ti.day, ti.quarter, ti.week, ti.day_name, ti.month_name
        FROM time_dimension ti WHERE day_name NOT IN ('Saturday','Sunday')
        AND ti.db_date NOT IN (SELECT startdate FROM tbl_holidays);

Answer 2

您可以使用NOT EXISTS排除假期：

SELECT *
FROM time_dimension ti
WHERE
    NOT EXISTS(SELECT 1 FROM tbl_holidays WHERE startdate = ti.db_date)
    AND day_name IN ('Monday','Tuesday','Wednesday','Thursday','Friday');

没有周末和假期的桌子。 MYSQL

2 个答案: