Pogressive numeration jquery

Question

我需要使用jquery逐步计算。我有一张桌子，一个td是这样的：

 <td class="number"></td>

我在jquery官方网站上看到这段代码

 $( "li" ).each(function( index ) {
    console.log( index + ": " + $( this ).text() );
 });

我尝试了这样的代码

 $( ".number" ).each(function( index ) {
    var num = ( index)+1;
 });
 $(".number").text(num)

但不会做任何事情

Answer 1

private void addDrawerItems() {
    String[] osArray = { "Android", "black" };
    //create also an array of paths to html files
    final String[] pathsArray = { "file:///android_asset/www/help.html", "HERE_MUST_BE_ANOTHER_PATH_TO_ANOTHER_FILE" };
    mAdapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, osArray);
    mDrawerList.setAdapter(mAdapter);

    mDrawerList.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            Toast.makeText(MainActivity.this, "Time for an upgrade!", Toast.LENGTH_SHORT).show();
            //load file to webView from pathsArray
            // getting current path from arg. position
            mWebView.loadUrl(pathsArray[position]);
            //close drawer
            mDrawerLayout.closeDrawers();

        }
    });
}

Answer 2

您的问题并不是很明显，但如果您想将每个td的编号放在其中，请使用以下代码：

$('.number').each(function(index){
    $(this).html(index + 1);
});

循环内的$(this)指向循环中的当前td ...