使用多机设置时,是否可以颠倒从最里面到最外面的供应商的顺序?我想要一个小的shell配置器在配置puppet之前在/etc/facter/facts.d/中创建一些事实,以尽可能地模仿我们当前的设置。 (我继承了一个大型的木偶仓库,并且在我开始做更改之前,我正试图为它创建一个Vagrant testbed。)
每个框的木偶设置都相同,但需要首先运行shell配置程序。这是一个示例Vagrantfile,用于显示我想要做的事情(更改了一些名称以保护无辜者):
$facts =<<FACTS
set -x
mkdir -p /etc/facter/facts.d
echo role=$1 > /etc/facter/facts.d/role.txt
echo location=$2 > /etc/facter/facts.d/location.txt
echo environment=$3 > /etc/facter/facts.d/environment.txt
FACTS
Vagrant.configure(2) do |config|
config.vm.box = "centos-6.6"
config.vm.synced_folder "hiera", "/etc/puppet/hiera"
config.vm.provision :puppet do |puppet|
puppet.manifest_file = "site.pp"
puppet.module_path = ["modules", "internal"]
puppet.hiera_config_path = "hiera.yaml"
puppet.options = "--test"
end
config.vm.define :foo1 do |c|
c.vm.hostname = "foo-1.vagrant"
c.vm.provision :shell, inline: $facts, args: "foo testing stage"
end
config.vm.define :bar do |c|
c.vm.hostname = "bar-1.vagrant"
c.vm.provision :shell, inline: $facts, args: "bar testing stage"
end
# ... more machines omitted ...
end
答案 0 :(得分:0)
回答我自己的问题,因为我找到了一个可接受的解决方法:我将木偶配置移动到内部块中。这是我当前代码的样子:
$facts =<<SET_FACTS
set -x
mkdir -p /etc/facter/facts.d
echo role=$1 > /etc/facter/facts.d/role.txt
echo location=$2 > /etc/facter/facts.d/location.txt
echo environment=$3 > /etc/facter/facts.d/environment.txt
SET_FACTS
module Vagrant
module Config
module V2
class Root
def provision(role, location, environment)
vm.provision "set-facts",
type: :shell,
inline: $facts,
args: [role, location, environment].map { |x| x.to_s }
vm.provision :puppet do |puppet|
puppet.manifest_file = "site.pp"
puppet.module_path = ["modules", "internal"]
puppet.hiera_config_path = "hiera.yaml"
end
end
end
end
end
end
Vagrant.configure(2) do |config|
config.vm.box = "centos-6.6"
config.vm.synced_folder "hiera", "/etc/puppet/hiera"
config.vm.define :foo1 do |c|
c.vm.hostname = "foo-1.vagrant"
c.provision(:foo, :testing, :stage)
end
config.vm.define :bar1 do |c|
c.vm.hostname = "bar-1.vagrant"
c.provision(:bar, :testing, :stage)
end
end