Question

我测试是否在发生异常时再次在catch块中调用doSomething方法。如何验证是否做了什么＆＃39;被叫了两次？

要测试的类：

@Service
public class ClassToBeTested implements IClassToBeTested {

@Autowired
ISomeInterface someInterface;

public String callInterfaceMethod() {
 String respObj;
 try{
     respObj = someInterface.doSomething(); //throws MyException
 } catch(MyException e){
    //do something and then try again
    respObj = someInterface.doSomething();
 } catch(Exception e){
    e.printStackTrace();
  }
 return respObj;
 }
}

测试用例：

public class ClassToBeTestedTest
{
@Tested ClassToBeTested classUnderTest;
@Injectable ISomeInterface mockSomeInterface;

@Test
public void exampleTest() {
    String resp = null;
    String mockResp = "mockResp";
    new Expectations() {{
        mockSomeInterface.doSomething(anyString, anyString); 
        result = new MyException();

        mockSomeInterface.doSomething(anyString, anyString); 
        result = mockResp;
    }};

    // call the classUnderTest
    resp = classUnderTest.callInterfaceMethod();

    assertEquals(mockResp, resp);
}
}

Answer 1

以下内容应该有效：

public class ClassToBeTestedTest
{
    @Tested ClassToBeTested classUnderTest;
    @Injectable ISomeInterface mockSomeInterface;

    @Test
    public void exampleTest() {
        String mockResp = "mockResp";
        new Expectations() {{
            // There is *one* expectation, not two:
            mockSomeInterface.doSomething(anyString, anyString);

            times = 2; // specify the expected number of invocations

            // specify one or more expected results:
            result = new MyException();
            result = mockResp;
        }};

        String resp = classUnderTest.callInterfaceMethod();

        assertEquals(mockResp, resp);
    }
}

JMockit没有。时间API调用

1 个答案: