Question

此查询将拉动所有在列文件名

中具有无线电或荧光许可证的医生

select practitioner_id_numbers.pract_id
      , practitioner_id_numbers.id_number
      , practitioner_id_numbers.expiration_date
      , practitioner_id_numbers.documentname
      , practitioner_id_numbers.historical 
from practitioner_id_numbers 
group by practitioner_id_numbers.pract_id
          , practitioner_id_numbers.id_number
          , practitioner_id_numbers.expiration_date
          , practitioner_id_numbers.documentname
          , practitioner_id_numbers.historical 
 having (((practitioner_id_numbers.documentname) like "Radio*" 
        or (practitioner_id_numbers.documentname) like "Fluoro*") 
        and ((practitioner_id_numbers.historical)=0));

Answer 1

Microsoft Access创建自己的SQL版本，这实际上很烦人，因为它实际上向DBMS本身呈现了正确的SQL - 它只是不会将它暴露给最终用户。如果要使此DBMS兼容，则需要考虑Access为表创建了别名，并将架构/表分隔符从点转换为下划线。

因此，根据您的表名是practitioner.id_numbers还是practitioner_id.numbers，SQL会有所不同 - 假设它是后者，Oracle SQL将是：

select practitioner_id.numbers.pract_id
      , practitioner_id.numbers.id_number
      , practitioner_id.numbers.expiration_date
      , practitioner_id.numbers.documentname
      , practitioner_id.numbers.historical 
from practitioner_id.numbers 
group by practitioner_id.numbers.pract_id
          , practitioner_id.numbers.id_number
          , practitioner_id.numbers.expiration_date
          , practitioner_id.numbers.documentname
          , practitioner_id.numbers.historical 
 having (((practitioner_id.numbers.documentname) like 'Radio%'
        or (practitioner_id.numbers.documentname) like 'Fluoro%') 
        and ((practitioner_id.numbers.historical)=0));

另请注意，在Access中，双引号变为值的单个引号，而星号变为百分号。

要在Access中使相同的SQL工作，您可以将其作为pass-thru查询运行，然后您的代码将从那时开始可移植。唯一的缺点是，如果你进行pass-thru，你就不能再在Access中使用设计器了。

尽管如此，Access的另一个危险是，当having成为首选时，它往往会过度使用where。假设标准消除了大量行，以下代码在Oracle方面将更加高效：

select practitioner_id.numbers.pract_id
      , practitioner_id.numbers.id_number
      , practitioner_id.numbers.expiration_date
      , practitioner_id.numbers.documentname
      , practitioner_id.numbers.historical 
from practitioner_id.numbers 
where (((practitioner_id.numbers.documentname) like 'Radio%' 
        or (practitioner_id.numbers.documentname) like 'Fluoro%') 
        and ((practitioner_id.numbers.historical)=0))
group by practitioner_id.numbers.pract_id
          , practitioner_id.numbers.id_number
          , practitioner_id.numbers.expiration_date
          , practitioner_id.numbers.documentname
          , practitioner_id.numbers.historical

而且，只是为了咧嘴笑，如果你想让它变得更加惯用，你可以添加别名并将group by更改为distinct（因为你似乎并没有真正使用分组功能）：

select distinct
  pi.pract_id
 , pi.id_number
 , pi.expiration_date
 , pi.documentname
 , pi.historical 
from practitioner_id.numbers as pi
where
  ((pi.documentname like 'Radio%' or
    pi.documentname like 'Fluoro%') and
    pi.historical=0)

在Access中工作，但在SQL Oracle Developer中不起作用

1 个答案: