Question

我需要将zip文件中的所有文件从AAAAA-filename.txt重命名为BBBBB-filename.txt，我想知道是否可以自动执行此任务，而无需提取所有文件，重命名然后再压缩。一次解压缩，重新命名和再次压缩是可以接受的。

我现在拥有的是：

for file in *.zip
do
    unzip $file
    rename_txt_files.sh
    zip *.txt $file
done;

但是我不知道是否有一个更好的版本，我不必使用所有额外的磁盘空间。

Answer 1

<强>计划

查找带字符串的文件名偏移量

使用dd覆盖新名称（注意只能使用相同的文件名长度）。否则也必须找到并覆盖   filenamelength字段..

在尝试此

之前备份您的zipfile

<强> zip_rename.sh

#!/bin/bash

strings -t d test.zip | \
grep '^\s\+[[:digit:]]\+\sAAAAA-\w\+\.txt' | \
sed 's/^\s\+\([[:digit:]]\+\)\s\(AAAAA\)\(-\w\+\.txt\).*$/\1 \2\3 BBBBB\3/g' | \
while read -a line; do
  line_nbr=${line[0]};
  fname=${line[1]};
  new_name=${line[2]};
  len=${#fname};
#  printf "line: "$line_nbr"\nfile: "$fname"\nnew_name: "$new_name"\nlen: "$len"\n";
  dd if=<(printf $new_name"\n") of=test.zip bs=1 seek=$line_nbr count=$len conv=notrunc  
done;

<强>输出

$ ls
AAAAA-apple.txt  AAAAA-orange.txt  zip_rename.sh
$ zip test.zip AAAAA-apple.txt AAAAA-orange.txt 
  adding: AAAAA-apple.txt (stored 0%)
  adding: AAAAA-orange.txt (stored 0%)
$ ls
AAAAA-apple.txt  AAAAA-orange.txt  test.zip  zip_rename.sh
$ ./zip_rename.sh 
15+0 records in
15+0 records out
15 bytes (15 B) copied, 0.000107971 s, 139 kB/s
16+0 records in
16+0 records out
16 bytes (16 B) copied, 0.000109581 s, 146 kB/s
15+0 records in
15+0 records out
15 bytes (15 B) copied, 0.000150529 s, 99.6 kB/s
16+0 records in
16+0 records out
16 bytes (16 B) copied, 0.000101685 s, 157 kB/s
$ unzip test.zip 
Archive:  test.zip
 extracting: BBBBB-apple.txt         
 extracting: BBBBB-orange.txt        
$ ls
AAAAA-apple.txt   BBBBB-apple.txt   test.zip
AAAAA-orange.txt  BBBBB-orange.txt  zip_rename.sh
$ diff -qs AAAAA-apple.txt BBBBB-apple.txt 
Files AAAAA-apple.txt and BBBBB-apple.txt are identical
$ diff -qs AAAAA-orange.txt BBBBB-orange.txt 
Files AAAAA-orange.txt and BBBBB-orange.txt are identical

Answer 2

我们使用python

将xyz.zip文件提取到xyz_renamed/文件夹中
在renameFile函数中重命名所需的文件（我们仅重命名jpeg和png图像）（我们将名称更改为较低的名称）
在xyz_renamed.zip中再次打包重命名的内容
删除xyz_renamed/文件夹和xyz.zip文件
将xyz_renamed.zip重命名为xyz.zip

import os
from zipfile import ZipFile
import shutil

# rename the individual file and return the absolute path of the renamed file
def renameFile(root, fileName):
    toks = fileName.split('.')
    newName = toks[0].lower()+'.'+toks[1]
    renamedPath =  os.path.join(root,newName)
    os.rename(os.path.join(root,fileName),renamedPath)
    return renamedPath

def renameFilesInZip(filename):
    # Create <filename_without_extension>_renamed folder to extract contents into
    head, tail = os.path.split(filename)
    newFolder = tail.split('.')[0]
    newFolder += '_renamed'
    newpath = os.path.join(head, newFolder)
    if(not os.path.exists(newpath)):
        os.mkdir(newpath)

    # extracting contents into newly created folder
    print("Extracting files\n")
    try:
        with ZipFile(filename, 'r', allowZip64=True) as zip_ref:
            zip_ref.extractall(newpath)
        zip_ref.close()
    except ResponseError as err:
        print(err)
        return -1

    # track the files that need to be repackaged in the zip with renamed files
    filesToPackage = []

    for r, d, f in os.walk(newpath):
        for item in f:
            # filter the file types that need to be renamed
            if item.lower().endswith(('.jpg', '.png')):
                # renaming file
                renamedPath = renameFile(r, item)
                filesToPackage.append(renamedPath)
            else:
                filesToPackage.append(os.path.join(r,item))


    # creating new zip file
    print("Writing renamed file\n")

    zipObj = ZipFile(os.path.join(head, newFolder)+'.zip', 'w', allowZip64 = True)
    for file in filesToPackage:
        zipObj.write(file, os.path.relpath(file, newpath))
    zipObj.close()

    # removing extracted contents and origianl zip file
    print('Cleaning up \n')
    shutil.rmtree(newpath)
    os.remove(filename)

    # renaming zipfile with renamed contents to original zipfile name
    os.rename(os.path.join(head, newFolder)+'.zip', filename)

使用以下代码为多个zip文件调用重命名功能


if __name__ == '__main__':

    # zipfiles with contents to be renamed
    zipFiles = ['/usr/app/data/mydata.zip', '/usr/app/data/mydata2.zip']
    
    # do the renaming for all files one by one
    for _zip in zipFiles:
        renameFilesInZip(_zip)

如何在不提取和重新压缩它们的情况下重命名zip存档中的文件？

2 个答案: