Question

我有以下Android代码，这给出了400错误：

url = new URL(requestURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(15000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("GET");
conn.setDoInput(true);
conn.setDoOutput(true);

MySQLiteHelper db = new MySQLiteHelper(this);
String token = db.getLoginToken();
conn.setRequestProperty("Authorization", "Bearer " + token);

OutputStream os = conn.getOutputStream();

os.close();
int responseCode=conn.getResponseCode();

此代码为我提供了400响应代码。我正在尝试复制我们的iOS应用代码：

NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
    NSString *authorization = [NSString stringWithFormat:@"Bearer %@",token];
    [request setValue:authorization forHTTPHeaderField:@"Authorization"];
    [request setURL:[NSURL URLWithString:professionalConnections]];
    [request setHTTPMethod:@"GET"];
    [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

    NSURLConnection *conn = [[NSURLConnection alloc] initWithRequest:request delegate:self];

没有问题。

为什么Android代码会导致400错误？

Answer 1

您需要放置Content-Type标头

conn.setRequestProperty("Content-type", "application/x-www-form-urlencoded");

Android HttpURLConnection给出400错误

1 个答案: