我正在尝试调用外部命令并在<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="itemshead" style="margin-top:4px;"><div class="items">List of Items <span class="countdown"></span></div></div>
生成时将其输出打印出来。我在JavaFX中阅读了关于并发性的文档,我相信我做了我必须做的工作才能使它工作。
我正在使用TextArea
课程来完成我的工作:
Task
但是,我遇到以下异常:
public synchronized void run(ProcessBuilder processBuilder) throws IOException, InterruptedException {
ExternalCommandRunner self = this;
Thread taskThread = new Thread(new Task<Void>() {
@Override
public Void call() throws Exception {
setActive();
try {
runningProcess = processBuilder.start();
StreamPrinter inputStream = new StreamPrinter(runningProcess.getInputStream(), self::handleLog);
StreamPrinter errorStream = new StreamPrinter(runningProcess.getErrorStream(), self::handleLog);
outputTextArea.clear();
new Thread(inputStream).start();
new Thread(errorStream).start();
runningProcess.waitFor();
return null;
} finally {
stop.fire();
setInactive();
}
}
});
taskThread.setDaemon(true);
taskThread.start();
taskThread.join();
}
private void handleLog (String line) { Platform.runLater(() -> outputTextArea.appendText(line + "\n")); }
private void setActive () { setState(STOP_ACTIVE_ICON , false) ; }
private void setInactive() { setState(STOP_INACTIVE_ICON, true) ; }
private void setState (String iconPath, boolean disableButton) {
stop.setGraphic(imageViewFromResource(iconPath, Resources.class));
stop.setDisable(disableButton);
}
Exception in thread "Thread-5" java.lang.IllegalStateException: Not on FX application thread; currentThread = Thread-5
at com.sun.javafx.tk.Toolkit.checkFxUserThread(Unknown Source)
at com.sun.javafx.tk.quantum.QuantumToolkit.checkFxUserThread(Unknown Source)
at javafx.scene.Parent$2.onProposedChange(Unknown Source)
at com.sun.javafx.collections.VetoableListDecorator.setAll(Unknown Source)
at com.sun.javafx.collections.VetoableListDecorator.setAll(Unknown Source)
at com.sun.javafx.scene.control.skin.LabeledSkinBase.updateChildren(Unknown Source)
at com.sun.javafx.scene.control.skin.LabeledSkinBase.handleControlPropertyChanged(Unknown Source)
at com.sun.javafx.scene.control.skin.ButtonSkin.handleControlPropertyChanged(Unknown Source)
at com.sun.javafx.scene.control.skin.BehaviorSkinBase.lambda$registerChangeListener$61(Unknown Source)
at com.sun.javafx.scene.control.MultiplePropertyChangeListenerHandler$1.changed(Unknown Source)
at javafx.beans.value.WeakChangeListener.changed(Unknown Source)
at com.sun.javafx.binding.ExpressionHelper$SingleChange.fireValueChangedEvent(Unknown Source)
at com.sun.javafx.binding.ExpressionHelper.fireValueChangedEvent(Unknown Source)
at javafx.beans.property.ObjectPropertyBase.fireValueChangedEvent(Unknown Source)
at javafx.beans.property.ObjectPropertyBase.markInvalid(Unknown Source)
at javafx.beans.property.ObjectPropertyBase.set(Unknown Source)
at javafx.css.StyleableObjectProperty.set(Unknown Source)
at javafx.beans.property.ObjectProperty.setValue(Unknown Source)
at javafx.scene.control.Labeled.setGraphic(Unknown Source)
at com.dici.javafx.components.ExternalCommandRunner.setState(ExternalCommandRunner.java:66)
at com.dici.javafx.components.ExternalCommandRunner.setActive(ExternalCommandRunner.java:63)
at com.dici.javafx.components.ExternalCommandRunner.access$000(ExternalCommandRunner.java:19)
at com.dici.javafx.components.ExternalCommandRunner$1.call(ExternalCommandRunner.java:39)
at com.dici.javafx.components.ExternalCommandRunner$1.call(ExternalCommandRunner.java:36)
at javafx.concurrent.Task$TaskCallable.call(Unknown Source)
at java.util.concurrent.FutureTask.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)
只是一个stop
。我做得不对劲?从文档中,使用Button
这种方式就足够了......
答案 0 :(得分:1)
如果我做对了,堆栈跟踪只是说代码中还有另一行,其中一些UI控件是从FX应用程序线程外部操纵的 - 这一定不会发生。
应用程序代码的第一行代码(不是JDK代码)是:
在File.ReadAllAsync
这似乎是你的例子中的线条:
com.dici.javafx.components.ExternalCommandRunner.setState(ExternalCommandRunner.java:66)
如果stop只是一个按钮,方法setState()操纵它并从你自己的自定义线程调用,那么框架就会抱怨这种情况。
尝试在FX应用程序线程上设置操作UI控件的任何,就像在handleLog方法中使用stop.setGraphic(imageViewFromResource(iconPath, Resources.class));
stop.setDisable(disableButton);
一样。
答案 1 :(得分:0)
愚蠢的我。我想保证在另一个命令已经运行时没有人能够运行命令(并在文本区域打印输出),因此synchronized
和Thread.join
。但是,这是错误的。我也误解了Task
类的文档。
以下是我犯过的两个错误以及如何解决这些错误:
Thread.join
阻止FX应用程序线程,直到任务结束,因此文本区域中不会显示任何内容。我使用Semaphore
替换了此同步。信号量阻止第二个线程进入run
方法,并在后台线程终止时使用Task
侦听器方法释放。 FX应用程序线程立即退出该方法。
Task.call
实际上不能与任何JavaFX组件交互。只允许侦听器方法(cancelled
,succeeded
,failed
)这样做。因此,我将对setActive
和setInactive
的调用提取到call
方法之外。
演示这些更改的代码如下:
private final Semaphore runMutex = new Semaphore(1);
public void run(ProcessBuilder processBuilder) throws IOException, InterruptedException {
runMutex.acquire();
setActive();
ExternalCommandRunner self = this;
Thread taskThread = new Thread(new Task<Void>() {
@Override
public Void call() throws Exception {
runningProcess = processBuilder.start();
StreamPrinter inputStream = new StreamPrinter(runningProcess.getInputStream(), self::handleLog);
StreamPrinter errorStream = new StreamPrinter(runningProcess.getErrorStream(), self::handleLog);
outputTextArea.clear();
new Thread(inputStream).start();
new Thread(errorStream).start();
runningProcess.waitFor();
return null;
}
@Override protected void cancelled() { super.cancelled(); terminate(); }
@Override protected void failed () { super.failed (); terminate(); }
@Override protected void succeeded() { super.succeeded(); terminate(); }
private void terminate() {
stop.fire();
setInactive();
runMutex.release();
}
});
taskThread.setDaemon(true);
taskThread.start();
}