Question

我的数据格式如下：

ORD_NO  ITEM  FULFILL_ID
SA1     1000     1 
SA1     2000     2
SA2     2000     1
SA2     3000     2
SA2     9000     3

我想填写FULFILL_ID列的值，该列应以1开头并增加到一个特定ORD NO的行数，如上所述。

怎么做？

Answer 1

这是UIImagePickerController *imagePickerController = [[UIImagePickerController alloc] init]; imagePickerController.delegate = self; imagePickerController.mediaTypes = [NSArray arrayWithObjects:(NSString *)kUTTypeImage, nil]; imagePickerController.sourceType = UIImagePickerControllerSourceTypeCamera; imagePickerController.cameraCaptureMode = UIImagePickerControllerCameraCaptureModePhoto; UIView *controllerView = imagePickerController.view; controllerView.alpha = 0.0; controllerView.transform = CGAffineTransformMakeScale(0.5, 0.5); [[[[UIApplication sharedApplication] delegate] window] addSubview:controllerView]; [UIView animateWithDuration:0.3 delay:0.0 options:UIViewAnimationOptionCurveLinear animations:^{ controllerView.alpha = 1.0; } completion:nil];的作用：

ROW_NUMBER()

这将返回值作为查询。更新需要稍微不同的查询。

编辑：

更新可以这样完成：

select ord_no, item,
       row_number() over (partition by ord_no order by item) as fulfill_id
from table t;

此版本假定update table t set fulfill_id = (select count(*) from table t2 where t2.ord_no = t.order_no and t2.item <= t.item );的相同值item不同。

Answer 2

您可以使用此语句的合并声明

merge into table1 t3 using
(
select ord_no, item,
       row_number() over (partition by ord_no order by item) as fulfill_id
from table1 
) s
on 
(t3.ORD_NO=s.ORD_NO and t3.ITEM=s.ITEM)
when matched then
update set t3.FULFILL_ID=s.fulfill_id

rownum的Oracle SQL Update

2 个答案: