Question

我有sequelize的问题。这就是我想要做的事情：

return pointsTransaction.findAndCountAll({
    where:{
        user_id: userId
    },
    limit: opts.limit,
    offset: opts.offset,
    include:[{
        model:sequelize.models.pointsPendingtransaction
    }]
});

生成的查询如下所示：

SELECT "pointsTransaction".*,
"pointsPendingtransactions"."transaction_ptr_id" AS "pointsPendingtransactions.transactionPtrId",
"pointsPendingtransactions"."is_active" AS "pointsPendingtransactions.isActive",
"pointsPendingtransactions"."transaction_id" AS "pointsPendingtransactions.transaction_id" 
FROM (
SELECT "pointsTransaction"."id",
"pointsTransaction"."date_time" AS "dateTime",
"pointsTransaction"."details",
"pointsTransaction"."points",
"pointsTransaction"."user_id" 
FROM "points_transaction" AS "pointsTransaction" 
WHERE "pointsTransaction"."user_id" = 10002 LIMIT 1000
) AS "pointsTransaction" 
LEFT OUTER JOIN "points_pendingtransaction" AS "pointsPendingtransactions" 
ON "pointsTransaction"."id" = "pointsPendingtransactions"."transaction_id"

所以在SQL中我只需要在查询结束时添加该行以使其正常工作：WHERE "pointsPendingtransactions"."transaction_id" IS null

所以我的问题是，我怎么能用续集来做到这一点？我尝试了许多不同的方法，但没有人工作......

Answer 1

尝试做下一步

        where: {
            transaction_id: {
              $eq: null
            }
        }

生成IS NULL

return pointsTransaction.findAndCountAll({
    where:{
        user_id: userId
    },
    limit: opts.limit,
    offset: opts.offset,
    include:[{
        model:sequelize.models.pointsPendingtransaction,
        where: {
            transaction_id: {
              $eq: null
            }
        }
    }]
});

Answer 2

如果您正在使用Sequelize.Op中的Sequelize符号运算符，则...

def __str__(self):
    return u'%s' % (self.shipper_number)

关系为null的sequelize

2 个答案: