如何基于主键Sql Server将XML数据更新到表中

Question

我有这样的XML字符串：

LanguageId int 
Language Varchar(50)
UserID INT

表

$sql5="update sms set sms='$remaining_sms' WHERE username='$session_username'";
$result5=mysql_query($sql5);

Answer 1

假设你在一个名为@input的SQL变量中使用了这个XML（假设你已经将“语言”修复为整个XML的“语言”正确拼写）那么你可以使用这样的东西来提取信息：

;WITH XmlData AS
(
    SELECT
        UserId = XC.value('(UserID)[1]', 'int'),
        LanguageId = XC.value('(LanguageId)[1]', 'int'),
        [Language] = XC.value('(Language)[1]', 'varchar(50)')
    FROM
        @input.nodes('/ArrayOfSpokenLanguageInfo/SpokenLanguageInfo') AS XT(XC)
)
SELECT *
FROM XmlData

这会为您提供如下输出：

更新：如果您只想插入新项目而只插入有UserId的项目，您可以使用以下内容：

;WITH XmlData AS
(
    SELECT
        UserId = XC.value('(UserID)[1]', 'int'),
        LanguageId = XC.value('(LanguageId)[1]', 'int'),
        [Language] = XC.value('(Language)[1]', 'varchar(50)')
    FROM
        @input.nodes('/ArrayOfSpokenLanguageInfo/SpokenLanguageInfo') AS XT(XC)
)
INSERT INTO dbo.YourTable(UserId, LanguageId, [Language])
   SELECT    
      x.UserId, x.LanguageId, x.[Language]
   FROM 
      XmlData x
   WHERE
      x.UserId IS NOT NULL
      AND NOT EXISTS (SELECT * FROM dbo.YourTable tbl
                      WHERE tbl.UserId = x.UserId)