Question

我遇到if if then statemenT的问题。我正在制作一个程序，告诉用户他是否输入一个整数，如果他得到100则为ex。这个程序的问题是如果我输入50，它将打印F和D标记。我觉得我的支架是罪魁祸首。如果你能提供帮助，那就太好了。

import java.util.Scanner;

public class LoanQualificationProgram{
   public static void main(String[] args){
      Scanner keyboard = new Scanner(System.in);
      int grade;
      grade = keyboard.nextInt();

      if (grade >=80) 
        System.out.println("Your grade is an A");
      else {
        if (grade >=70)
           System.out.println("Your grade is B");
        else {
          if (grade>=60)
             System.out.println("your grade is a C");
          else {
             if (grade >=50)
                System.out.println("your grade is a D");
             if (grade >=0)
                System.out.println("your grade is an F");
          }
        }
      }

Answer 1

您不需要嵌套这些陈述。要有效地使用else-if，请尝试以下方法：

if (grade >=80) {
  // A...
}
else if (grade >=70) {
  // B...
}
else if (grade>=60) {
  // C...
}
// ...
else {
  // Finally...
}

Answer 2

试试这个兄弟或用例陈述：）

if (grade >=80) 
  System.out.println("Your grade is an A");
else if(grade >=70)
    System.out.println("Your grade is B");
else if (grade>=60)
      System.out.println("your grade is a C");
else if (grade >=50)
        System.out.println("your grade is a D");
else if(grade >=0)
        System.out.println("your grade is an F");

嵌套如果是Java语句（基本）

2 个答案: