以更好的方式处理带有可变信息的POST请求...使用Flask

时间:2015-09-27 15:11:53

标签: python html post flask request

我有一个带有4个引导按钮的客户端应用程序,想要读取每个按钮的状态。打开按钮将发送" L1 / 2/3 / 4ON"的适当POST请求。我是这样做的;

@app.route("/param=L3ON", methods=['POST'])
def handle_L3():
 if request.method == 'POST':
   #########################
   # DO SOMETHING
   #########################
  return 'OK'

@app.route("/param=L2ON", methods=['POST'])
def handle_L2():
if request.method == 'POST':
   #########################
   # DO SOMETHING
   #########################
return 'OK'

@app.route("/param=L1ON", methods=['POST'])
def handle_L1():
 if request.method == 'POST':
   #########################
   # DO SOMETHING
   #########################
 return 'OK'

@app.route("/param=L4ON", methods=['POST'])
def handle_L4():
 if request.method == 'POST':
   #########################
   # DO SOMETHING
   #########################
 **strong text**return 'OK'  

我的javascript代码(在客户端)就像;

function ON(value) {
    var request = new XMLHttpRequest();
        if (value==="L1") {
         request.open("POST","param=L1ON", true);
        }else if (value==="L2") {
             request.open("POST","param=L2ON", true);
        }else if (value==="L3") {
             request.open("POST","param=L3ON", true);     
        }else if (value==="L4") {
             request.open("POST","param=L4ON", true);    
        }
        request.send(null);
  } 

我正在寻找一种更好的方法,而不是为每个人制作单独的处理程序。有没有办法可以检查POST请求的某些部分,即@ app.route(" / param =",methods = [' POST']),然后我可以进一步通过使用" request"查找该请求中的相应字符来检查它是哪个请求。 ?

1 个答案:

答案 0 :(得分:2)

您可以使用网址转换器:

@app.route('/param=<name>')
def handle(name):
    if request.method == 'POST':
        if name == 'L1ON':
           #do something
        elif name == 'L4ON':
           #do something

     return 'ok'