要将String转换为Hexadecimal,我正在使用:
public String toHex(String arg) {
return String.format("%040x", new BigInteger(1, arg.getBytes("UTF-8")));
}
这在最高投票的答案中概述: Converting A String To Hexadecimal In Java
我该怎么做反向,即十六进制到字符串?
答案 0 :(得分:2)
您可以从转换后的字符串重建bytes[]
,
这是一种方法:
public String fromHex(String hex) throws UnsupportedEncodingException {
hex = hex.replaceAll("^(00)+", "");
byte[] bytes = new byte[hex.length() / 2];
for (int i = 0; i < hex.length(); i += 2) {
bytes[i / 2] = (byte) ((Character.digit(hex.charAt(i), 16) << 4) + Character.digit(hex.charAt(i + 1), 16));
}
return new String(bytes);
}
另一种方法是使用DatatypeConverter
包中的javax.xml.bind
:
public String fromHex(String hex) throws UnsupportedEncodingException {
hex = hex.replaceAll("^(00)+", "");
byte[] bytes = DatatypeConverter.parseHexBinary(hex);
return new String(bytes, "UTF-8");
}
要验证的单元测试:
@Test
public void test() throws UnsupportedEncodingException {
String[] samples = {
"hello",
"all your base now belongs to us, welcome our machine overlords"
};
for (String sample : samples) {
assertEquals(sample, fromHex(toHex(sample)));
}
}
注意:由于00
方法中的fromHex
填充,仅需要在"%040x"
中删除前导toHex
。
如果您不介意用简单的%x
替换它,
然后你可以在fromHex
中删除这一行:
hex = hex.replaceAll("^(00)+", "");
答案 1 :(得分:0)
String hexString = toHex("abc");
System.out.println(hexString);
byte[] bytes = DatatypeConverter.parseHexBinary(hexString);
System.out.println(new String(bytes, "UTF-8"));
输出:
0000000000000000000000000000000000616263
abc