Question

我在破坏代码的MySQL查询中添加了两行（下面）。我无法弄清楚需要改变什么。我检查了所有相关文件。我得到的错误是：“表格中没有数据”作为DataTable中的响应。如果没有这两行，它就能完美运行。

A行

lp.image AS Picture,

B行

JOIN LetterIT lp ON lp.letterid = lst.letterid

下面您可以看到带有添加行的模型，视图和控制器。

模型（相关代码段）

public function get_letter_feed($user_id) { 
$sql = " 
    SELECT 
        l.uuid AS Uuid, 
        ls.`statcode` AS StatusCode, 
        ls.`statname` AS StatusDescription, 
        lst.shortnotes AS Notes, 
        lp.image AS Picture,
        CONCAT(LEFT(l.messages, 65), '') AS MessageBody, 
        l.rcpnt AS Recipient, 
        lst.createdtime AS Created
    FROM Letters l
    JOIN LetterAT lst ON lst.letterid = l.id AND lst.deleted IS NULL
    JOIN LetterST ls ON ls.id=lst.statusId
    JOIN LetterIT lp ON lp.letterid = lst.letterid
    WHERE 
        l.ownerId = {$this->db->escape($user_id)}
    ORDER BY lst.created DESC
    LIMIT 10;";
return $this->db->query($sql)->result();  
}

查看（相关代码段）

<table id="tableDataset">
 <thead>
  <tr>
     <th>Recipient</th>
     <th>Message Body</th>
     <th>Date</th>
     <th>Status</th>
  </tr>
</thead>
<tbody>
  <?foreach($letter_feed as $feed_item): ?>
     <tr>
        <td><?=$feed_item->Recipient?> </td> 
        <td><?=$feed_item->MessageBody?> </td>
        <td><?=$feed_item->Created?>  </td>
        <td><?=$feed_item->StatusDescription?> <a href="<?=$feed_item->Picture?>" data-lightbox="photo"><b>(PHOTO)</b></a> </td>
     </tr>
  <?endforeach?>
</tbody>

控制器（相关代码段）

public function get_letter_status_feed_html() {
$letter_feed = $this->Letter_model->get_letter_feed($this->user->userId);
$this->load->view('dashboard/snippet/letter_status_feed', array('letter_feed'=>$letter_feed));
}

如果我遗失了什么，请告诉我:)

MySQL查询中的小变化，现在返回无数据？

0 个答案: