我使用以下代码搜索专栏"英语"。还有一个名为" BANGLA"的专栏。我应该如何修改代码,以便" ENGLISH"和" BANGLA"同时搜索列并作为组合结果返回?
public List<Bean> getWords(String englishWord) {
if(englishWord.equals(""))
return new ArrayList<Bean>();
String sql = "SELECT * FROM " + TABLE_NAME +
" WHERE " + ENGLISH + " LIKE ? ORDER BY " + ENGLISH + " LIMIT 100 ";
SQLiteDatabase db = initializer.getReadableDatabase();
Cursor cursor = null;
try {
cursor = db.rawQuery(sql, new String[]{"%" + englishWord + "%"});
List<Bean> wordList = new ArrayList<Bean>();
while(cursor.moveToNext()) {
int id = cursor.getInt(0);
String english = cursor.getString(1);
String bangla = cursor.getString(2);
String status = cursor.getString(3);
wordList.add(new Bean(id, english, bangla, status));
}
return wordList;
} catch (SQLiteException exception) {
exception.printStackTrace();
return null;
} finally {
if (cursor != null)
cursor.close();
}
}
我将String sql
修改为
String sql = "SELECT * FROM " + TABLE_NAME +
" WHERE " + ENGLISH + " LIKE ? ORDER BY " + ENGLISH + " LIMIT 100 " + " UNION ALL " + " SELECT * FROM " + TABLE_NAME +
" WHERE " + BANGLA + " LIKE ? ORDER BY " + ENGLISH + " LIMIT 100";
然而,这不起作用。我收到了这个错误:
ORDER BY clause should come after UNION ALL not before (code 1): , while compiling: SELECT * FROM words WHERE en_word LIKE ? ORDER BY en_word LIMIT 100 UNION ALL SELECT * FROM words WHERE bn_word LIKE ? ORDER BY en_word LIMIT 100
答案 0 :(得分:1)
你需要将ORDER BY和LIMIT移到最后:
SELECT * FROM TABLE_NAME
WHERE ENGLISH LIKE ?
UNION ALL
SELECT * FROM tull
WHERE BANGLA LIKE ?
ORDER BY ENGLISH LIMIT 100
然而,这只会按英文排序,并且总共限制为100行。你是否需要每种语言100行?如果您想按两种语言订购,您可以使用别名对列进行别名并按顺序排序:
SELECT *, ENGLISH AS TEXT FROM tull
WHERE ENGLISH LIKE ? OR BANGLA LIKE ?
UNION ALL
SELECT *, BANGLA AS TEXT FROM tull
WHERE BANGLA LIKE ""
ORDER BY TEXT LIMIT 100;
您仍然需要将第二个选择参数添加为评论中提到的jyank。