Question

我想要一个带有N个零的数组，比如

#define STRIDE 3
struct MtNode{
    /* nodes stores pointers to its 2^stride child nodes.*/
    /* you are using C, so struct is needed here */
    struct MtNode* nodes;  // 2^stride = 2^3 = 8
    int   nexthop;
};

/* Initialize binary trie node */
/* in C, struct is needed beefure MtNode */
struct MtNode* init_mtnode(){
    struct MtNode *ret = malloc(sizeof(struct MtNode));
    int size = (int)pow(2,STRIDE);
    ret->nodes = malloc( sizeof(struct MtNode) * size );
    for (int i=0; i<(int)pow(2,STRIDE); ++i)
        /* ret->nodes[i] has type struct MtNode, not struct MtNode* */
        /* (ret->nodes[i]) = NULL; */
        {
            ret->nodes[i].nodes = NULL;
            ret->nodes[i].nexthop = -1;
        }
    ret->nexthop = -1;
    return ret;
}

我可以做一个for-loop并将它们全部推出，但有更好的方法吗？

[0,0,0,0...0]

Answer 1

使用Int8Array：

var x = new Int8Array(100)
# x now is filled with 0s and is of size 100

Int8Array 类型数组表示二进制补码8 - 有符号整数的数组。内容初始化为0。

另请参阅：http://www.ecma-international.org/ecma-262/6.0/#table-49

如何使用N个零创建数组？

1 个答案: