Question

我正在研究基于数据的大型项目。我为PHP中的每个数据创建了数组。现在我想将它插入到MySQL数据库中。

<?php
$servername = "localhost";
$username = "xxxx";
$password = "xxxxx";
$db_name = "xxxxxxx";

// Create connection
$link = mysql_connect($servername, $username, $password);

if(!$link){
echo "Failed" .mysql_connect_error();
}

mysql_select_db($db_name);

 $data =   array (
        [1] => array(
            'eng_title' => "john",
            'content' => "john",
            'category' => "john",

        ), 
        [2] => array(
            'eng_title' => "john",
            'content' => "john",
            'category' => "john",
        ), 
        [3] => array(
            'eng_title' => "john",
            'content' => "john",
            'category' => "john",
        ), 
     );

if(is_array($data)){

    $sql = "INSERT INTO `table_a`( `eng_title`, `content`, `category`) values";

    $valuesArr = array();
    foreach($data as $row){

        $eng_title = mysql_real_escape_string( $row['eng_title'] );
        $content = mysql_real_escape_string( $row['content'] );
        $category = mysql_real_escape_string( $row['category'] );


        $valuesArr[] = "('$eng_title', '$content', '$category')";
    }

   $sql .= implode(',', $valuesArr);
    echo $sql;
    mysql_query($sql) or exit(mysql_error()); 

}

?>

这是执行代码时出现的消息。

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

我在其他程序中使用MySQLi，我想我使用最新版本的MySQL，这就是为什么上述程序无效。

Answer 1

因为我认为你在“内爆”中遗漏了一些东西。试试这个 -

if(is_array($data)){

    $sql = "INSERT INTO `table_a`( `eng_title`, `content`, `category`) values";

    $valuesArr = array();
    $last=count($valuesArr);
    $i=0;
    foreach($data as $row){

        $eng_title = mysql_real_escape_string( $row['eng_title'] );
        $content = mysql_real_escape_string( $row['content'] );
        $category = mysql_real_escape_string( $row['category'] );


        $sql .= "('$eng_title', '$content', '$category')";
        if($i<$last)
           $sql .=" , ";
     $i++;
    }


    echo $sql;
    mysql_query($sql) or exit(mysql_error()); 

}

Answer 2

使用PDO，最好看一下：Choosnig an API

要使用PDO执行insert语句，您可以在此处查看更多示例：PDO - Manual

因此，对于您的情况，您可以通过两种方式实现：

<强> 1。在每个循环上插入一行：

<?php 

$data =   array (
    1 => array(
        'eng_title' => "john",
        'content' => "john",
        'category' => "john",

    ), 
    2 => array(
        'eng_title' => "john",
        'content' => "john",
        'category' => "john",
    ), 
    3 => array(
        'eng_title' => "john",
        'content' => "john",
        'category' => "john",
    ), 
 );

$servername = "localhost";
$username = "xxxx";
$password = "xxxxx";
$db_name = "xxxxxxx";
$pdo = new PDO("mysql:host=$servername;dbname=$db_name", "$username", "$password");
foreach ($data as $key => $value) {
    $eng_title = mysql_real_escape_string( $value['eng_title'] );
    $content = mysql_real_escape_string( $value['content'] );
    $category = mysql_real_escape_string( $value['category'] );

    $query = $db->prepare('INSERT INTO table_a(eng_title, content, category) VALUES(:title, :content, :category)');
    $query->bindParam("title", $eng_title);
    $query->bindParam("content", $content);
    $query->bindParam("category", $category);
    $query->execute();
}

<强> 2。创建一个SQL语句并执行它：

<?php 

$data =   array (
    1 => array(
        'eng_title' => "john",
        'content' => "john",
        'category' => "john",

    ), 
    2 => array(
        'eng_title' => "john",
        'content' => "john",
        'category' => "john",
    ), 
    3 => array(
        'eng_title' => "john",
        'content' => "john",
        'category' => "john",
    ), 
 );

$servername = "localhost";
$username = "xxxx";
$password = "xxxxx";
$db_name = "xxxxxxx";
$pdo = new PDO("mysql:host=$servername;dbname=$db_name", "$username", "$password");

$query = "INSERT INTO table_a(eng_title, content, category) VALUES";

$counter = 0;
$arraySize = sizeof($data);
foreach ($data as $key => $value) {
    $eng_title = mysql_real_escape_string( $value['eng_title'] );
    $content = mysql_real_escape_string( $value['content'] );
    $category = mysql_real_escape_string( $value['category'] );

    $counter++;
    $query .= "($eng_title, $content, $category)";
    if($counter < $arraySize)
        $query .= ",";
}
$pdo->query($query);

希望它会对你有所帮助。

使用PHP将数组数据值插入MySQL数据库表

2 个答案: