Question

我可能会遗漏一些显而易见的东西但是可以使用<?PHP $servername = "localhost"; $username = "root"; $password = ""; $dbname = "lms"; $conn = mysqli_connect($servername, $username, $password, $dbname); $empid = (isset($_POST['empid']) ? $_POST['empid'] : ''); $month = (isset($_POST['month']) ? $_POST['month'] : ''); $month = "2015-sep"; $month1 = date('F', strtotime('$month')); //echo $month1; $year = date('Y',strtotime('$month')); $monthStart = date("Y-m-1") . "<br/>"; $num = cal_days_in_month(CAL_GREGORIAN, date("m"), date("Y")); $monthEnd = date("Y-m-".$num)."<br/>"; //echo "$num"; $months = date('M'); $years = date ('Y'); $leave = 0; if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SELECT `startdate`, `enddate`,`duration` FROM `leaves` WHERE `employee` = '2' AND `status` = '3' AND `startdate` > '01-09-2015' AND `enddate` < '30-09-2015' "; $result = $conn->query($sql); if ($result->num_rows > 0) { // output data of each row while($row = $result->fetch_assoc()) { $start = ($row['startdate']); $end = ($row['enddate']); $startcount = ['COUNT(`employee`)']; //$durationlvs = ($row['duration']); echo "sdate:$start,edate:$end</br>"; //echo "lvsdur:$durationlvs"; } function getLeavesInPeriod($start, $end) { $date = new DateTime($start); $endDate = new DateTime($end); $leaves = array(); while( $date <= $endDate ) { $year = $date->format('Y'); $month = $date->format('M'); if(!array_key_exists($year, $leaves)) $leaves[$year] = array(); if(!array_key_exists($month, $leaves[$year])) $leaves[$year][$month] = 0; $leaves[$year][$month]++; $date->modify("+1 day"); } return $leaves; } $leaves = getLeavesInPeriod($start,$end); $noofleaves=$leaves[$years][$months]; echo $noofleaves; $conn->close(); } ?>创建这样的JSON吗？

json_encode

更新

我必须从一开始就注意到我知道我所要求的味道很糟糕。然而，这正是SOLR所要求的。见http://wiki.apache.org/solr/UpdateJSON

Answer 1

不，json_encode不会为您提供重复键的结果，因为您编码的对象/数组不能拥有一个属性/键的多个值，但您可以存储相同的数据有两种不同的方式。最自然的可能是：

{
    "foo": ["bar", "baz"]
}

您还可以执行以下操作：

[
   { 
     "key": "foo",
     "value": "bar"
   }, 
   { 
     "key": "foo",
     "value": "baz"
   }
]

如果你必须获得SOLR的语法，你可以通过组合多次调用json_encode来获得它，虽然它不是很漂亮：

$foo1 = [ 'foo' => 'bar' ];
$foo2 = [ 'foo' => 'baz' ];

echo rtrim( json_encode( $foo1 ), '}' ) . ',' . ltrim( json_encode( $foo2 ), '{' );
// {"foo":"bar","foo":"baz"}

在PHP中使用相同的元素创建JSON

1 个答案: