Question

给定以下表结构，我想返回一个Eloquent集合，或者至少将原始DB结果转换为关联数组以便于迭代。

建筑物

+----+---------------+
| id | building_name |
+----+---------------+
|  1 | Building 1    |
|  2 | Building 2    |
+----+---------------+

房间

+----+-----------+-------------+
| id | room_name | building_id |
+----+-----------+-------------+
|  1 | Room 1    |           1 |
|  2 | Room 2    |           1 |
|  3 | Room 3    |           2 |
+----+-----------+-------------+

maintenancelog

+----+-------------------+---------+---------------------+
| id | maintenance_value | room_id |      created_at     |
+----+-------------------+---------+---------------------+
|  1 | Cleaned           |       1 | 2015-09-10 00:54:59 |
|  2 | Cleaned           |       1 | 2015-09-13 01:55:59 |
|  3 | Cleaned           |       2 | 2015-09-09 02:56:59 |
|  4 | Cleaned           |       2 | 2015-09-14 03:57:59 |
|  5 | Cleaned           |       3 | 2015-09-08 04:58:59 |
|  6 | Cleaned           |       3 | 2015-09-15 05:59:59 |
+----+-------------------+---------+---------------------+

现在使用以下原始数据库查询..

$results = DB::select('
  select b.building_name,r.room_name,x.maxdate FROM buildings b
  join rooms r on r.building_id = b.id
  join (select room_id,max(created_at) as maxdate from maintenancelog group by room_id) x on x.room_id=room.id
  having x.maxdate < DATE_SUB(NOW(), INTERVAL 10 DAY)');

返回

Array
(
    [0] => stdClass Object
        (
            [building_name] => Building 1
            [room_name] => Room 1
            [maxdate] => 2015-09-13 01:55:59
        )

    [1] => stdClass Object
        (
            [building_name] => Building 1
            [room_name] => Room 2
            [maxdate] => 2015-09-14 03:57:59 
        )

    [2] => stdClass Object
        (
            [building_name] => Building 2
            [room_name] => Room 3
            [maxdate] => 2015-09-15 05:59:59
        )

是否有给定数组的Laravel辅助函数，我可以指定键和分组命令吗？有点像，按building_name，room_name分组，这样它将返回一个带有＆＃34; buildings＆＃34;的集合或关联数组。和＆＃34;房间＆＃34;作为使迭代更容易的关键？我可以建立一个，但这似乎是一个常见的任务。（我做了搜索）

我使用Eloquent并为表格制作模型，但查询对我来说太复杂了，无法弄清楚如何将其变成Eloquent语句。那么即使有一种方法可以使用现有模型创建集合吗？

（注意我已经弄清楚如何使用关系和查询范围从维护日志 - >房间 - >建筑物向后工作。但它将建筑物置于关系的最低层，我希望它是第一个）

Answer 1

建筑类中的

：

public function rooms(){
    return $this->hasMany('App\Room');
}

在Room class：

public function maintenanceLog(){
    return $this->hasMany('App\MaintenanceLog');
}

在MaintenanceLog类中：

public function scopeLongest($query){ //you can name it as you like ofc.
    return $query->orderBy('created_at','desc')->first();
}

最后你可以使用：

foreach(Building::all() as $building){
    foreach($building->rooms() as $room){
        echo 'building: ' . $building->building_name . ' room: ' . $room->room_name . ' maxdate: ' . $room->maintenanceLog()->longest()->created_at;
    }
}

Answer 2

Laravel提供了一些可用于获取所需数组https://laravel.com/docs/5.1/collections#method-put https://laravel.com/docs/5.1/collections#introduction的收集方法。

为了从$ results中获取关联数组，例如

array:3 [
       "Building 1" => "Room 1"
       "Building 1" => "Room 2"
       "Building 1" => "Room 3"
]

要解决您的问题，请创建一个集合对象

$collection_obj = collect();

循环$ results

foreach ($results as $result) {
            $collection_obj->put($result->building_name, $result->room_name);
}

然后要将您的集合转换为数组，请使用toArray（）

$result_arr = $collection_obj->toArray();

我希望这可以解决您的问题或至少为了参考。

Laravel 5.1从原始DB（或只是一个数组）创建集合或关联数组

2 个答案: