Question

我会尝试简化我的案例：

offenses = {};

$(offenseTableID).find('tr').each(function (rowIndex, r) {
  // building JSON object named "offense" with object with 
  // information from the table row. 
  // console.log shows It's correct. I typically have 3 rows 
  // showing different information. 

// I am trying to extend offenses with what I constructed.                     
 $.extend(offenses, offense);

});

// after I'm done I'm printing my "offenses" JSON object, 
// expecting it to include everything that was added, but even if 
// I $.extend multiple times - it only remembers the last JSON 
// object that was $.extend'ed  Why? 

console.log(JSON.stringify(offenses));

Answer 1

这是因为对象必须具有唯一键。您不能简单地将新对象附加到现有对象并期望它有用。你真正想要的是一个数组的对象。

offenses = [];

$(offenseTableID).find('tr').each(function (rowIndex, r) {
  // building object named "offense" with object with 
  // information from the table row. 
  // console.log shows It's correct. I typically have 3 rows 
  // showing different information. 

  // I am trying to extend offenses with what I constructed.                     
  offenses.push(offense);

});

这将产生一个如下所示的数组：

[{name:'bob'},{name:'frank'}]

然后你可以将其字符串化为json：

[{"name":"bob"},{"name":"frank"}]

$ .extend只记住最后添加的对象

1 个答案: