所有
遇到ConcurrentModificationException问题并努力寻找解决方案,部分原因是我无法在迭代时看到我修改列表的位置...任何想法?我已经突出显示导致问题的那一行(it3.remove())。真的处于停滞状态......
编辑:Stacktrace:Exception in thread "Thread-4" java.util.ConcurrentModificationException
at java.util.ArrayList$Itr.checkForComodification(Unknown Source)
at java.util.ArrayList$Itr.next(Unknown Source)
at com.shimmerresearch.advancepc.InternalFrameAndPlotManager.subtractMaps(InternalFrameAndPlotManager.java:1621)
第1621行对应于上面引用的代码中的it3.remove()。
private void subtractMaps(ConcurrentSkipListMap<String, PlotDeviceDetails> firstMap, ConcurrentSkipListMap<String, PlotDeviceDetails> secondMap) {
// iterate through the secondmap
Iterator<Entry<String, PlotDeviceDetails>> it1 = secondMap.entrySet().iterator();
while (it1.hasNext()) {
Entry<String, PlotDeviceDetails> itEntry = (Entry) it1.next();
String mapKey = (String) it1Entry.getKey();
PlotDeviceDetails plotDeviceDetails = (PlotDeviceDetails)it1Entry.getValue();
// if we find an entry that exists in the second map and not in the first map continue
if(!firstMap.containsKey(mapKey)){
continue;
}
// iterate through a list of channels belonging to the secondmap
Iterator <PlotChannelDetails> it2 = plotDeviceDetails.mListOfPlotChannelDetails.iterator();
while (it2.hasNext()) {
PlotChannelDetails it2Entry = it2.next();
// iterate through a list of channels belonging to the firstmap
Iterator <PlotChannelDetails> it3 = firstMap.get(mapKey).mListOfPlotChannelDetails.iterator();
innerloop:
while(it3.hasNext()){
// if a channel is common to both first map and second map, remove it from firstmap
PlotChannelDetails it3Entry = it3.next();
if(it3Entry.mChannelDetails.mObjectClusterName.equals(it2Entry.mChannelDetails.mObjectClusterName)){
it3.remove(); // this line is causing a concurrentModificationException
break innerloop;
}
}
}
}
}
答案 0 :(得分:1)
plotDeviceDetails.mListOfPlotChannelDetails
和firstMap.get(mapKey).mListOfPlotChannelDetails
引用了相同的列表。
plotDeviceDetails
和firstMap.get(mapKey)
是否也引用相同的对象是未知的,但没有更多信息,但它们共享频道列表。
答案 1 :(得分:1)
堆栈跟踪显示mListOfPlotChannelDetails
是ArrayList
,并且由于堆栈跟踪也显示错误来自it3.remove()
,并且代码中没有任何内容可以因此,您真正面临并发修改,即另一个线程已更新ArrayList
被it3
迭代。
请记住,ArrayList
不支持并发多线程访问。