Question

任何人都可以帮我解决MySQL如何读取我试图执行此查询的行。

SELECT * FROM attendance where '2010-07-13 00:06:00' BETWEEN timein AND timeout;

这是表格中的日期：

+-----------------------+-----------------------+
|  timein               |  timeout              |
------------------------+------------------------
|  2010-07-13 23:44:11  |  2010-07-14 08:01:14  |
|  2010-07-12 23:40:56  |  2010-07-13 08:00:52  |   
|  2010-07-10 05:49:32  |  2010-07-10 14:00:45  |
+-----------------------+-----------------------+

正如我们在表中看到的那样，第2行预计会满足日期验证，但是当我执行查询时，它不会返回任何结果。如果有替代查询可以帮助任何人。

Answer 1

您的查询没问题。它应该按预期工作：

CREATE TABLE attendance (id int, timein datetime, timeout datetime);

INSERT INTO attendance VALUES (1, '2010-07-13 23:44:11', '2010-07-14 08:01:14');
INSERT INTO attendance VALUES (2, '2010-07-12 23:40:56', '2010-07-13 08:00:52');
INSERT INTO attendance VALUES (3, '2010-07-10 05:49:32',' 2010-07-10 14:00:45');

SELECT * FROM attendance where '2010-07-13 00:06:00' BETWEEN timein AND timeout;
+------+---------------------+---------------------+
| id   | timein              | timeout             |
+------+---------------------+---------------------+
|    2 | 2010-07-12 23:40:56 | 2010-07-13 08:00:52 |
+------+---------------------+---------------------+
1 row in set (0.01 sec)

您确定timein和timeout字段的类型为datetime或timestamp吗？

更新：在@Psytronic's建议下面的评论之后，如果您的字段属于varchar类型，您的示例甚至会有用：

CREATE TABLE attendance (id int, timein varchar(100), timeout varchar(100));

INSERT INTO attendance VALUES (1, '2010-07-13 23:44:11', '2010-07-14 08:01:14');
INSERT INTO attendance VALUES (2, '2010-07-12 23:40:56', '2010-07-13 08:00:52');
INSERT INTO attendance VALUES (3, '2010-07-10 05:49:32',' 2010-07-10 14:00:45');

SELECT * FROM attendance where '2010-07-13 00:06:00' BETWEEN timein AND timeout;
+------+---------------------+---------------------+
| id   | timein              | timeout             |
+------+---------------------+---------------------+
|    2 | 2010-07-12 23:40:56 | 2010-07-13 08:00:52 |
+------+---------------------+---------------------+
1 row in set (0.00 sec)

但是，您的字段不应为varchar，因为上面的内容会进行字符串比较，而不是时间比较。

Answer 2

你会想做类似的事情：

SELECT * FROM attendance where timein >= '2010-07-13 00:06:00' and timeout <= '2010-07-13 17:00:00';

编辑：我在这里尊重专家，但这就是我要做的。

MySQL中的日期验证

2 个答案: