如何在python中垂直打印不同长度的2d列表

Question

事实上我试着这样做。

我有班级名片

class Card(object):
def __init__(self, value, folldown,canMove):
    self.value = value
    self.folldown = folldown
    self.canMove=canMove

我用它打印

for i in range(len(cards)):
  for j in range(len(cards[i])):
       print cards[i][j].value

我想打印不同尺寸的{2}列表a=[[0, 1], [0, 1, 2], [0, 1, 2, 3]]

我希望像这样打印

0 0 0
1 1 1
  2 2
    3

我试图像这样打印

for i in range(len(a)):
  for j in range(len(a[i])):
       print a[i][j]

但结果是

0
1
0
1
2
0
1 
2 
3 

Answer 1

a = [[0, 1], [0, 1, 2], [0, 1, 2, 3]]
print '\n'.join(['\t'.join([str(x[i]) if len(x) > i else '' for x in a]) for i in range(len(max(a)))])

#0    0    0
#1    1    1
#     2    2
#          3

Answer 2

另一个一线解决方案

a = [[0, 1], [0, 1, 2], [0, 1, 2, 3]]
from itertools import izip_longest
print "\n".join(("\t".join(map(str,l)) for l in izip_longest(*a, fillvalue="")))

你得到：

0   0   0
1   1   1
    2   2
        3