Question

我正在制作Android应用程序，允许登录注册并获取数据，如用户ID，电话号码，...... 进程运行良好，但来的数据总是空的。

以下是Android中仅用于登录的功能，注册和获取数据的功能与其他参数相同

 private class AsyncDataClass extends AsyncTask<String, Void, String> {

    @Override
    protected String doInBackground(String... params) {

        HttpParams httpParameters = new BasicHttpParams();
        HttpConnectionParams.setConnectionTimeout(httpParameters, 5000);
        HttpConnectionParams.setSoTimeout(httpParameters, 5000);

        HttpClient httpClient = new DefaultHttpClient(httpParameters);
        HttpPost httpPost = new HttpPost(params[0]);

        String jsonResult = "";
//assigning the Params from EditText(s)
        try {
            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
            nameValuePairs.add(new BasicNameValuePair("username", params[1]));
            nameValuePairs.add(new BasicNameValuePair("password", params[2]));
            httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

            HttpResponse response = httpClient.execute(httpPost);
            jsonResult = inputStreamToString(response.getEntity().getContent()).toString();

        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return jsonResult;
    }
    @Override
    protected void onPreExecute() {
        super.onPreExecute();
    }
    @Override
    protected void onPostExecute(String result) {
        super.onPostExecute(result);
        System.out.println("Resulted Value: " + result);
        if(result.equals("") || result == null){
            pDialog.dismiss();
            Toast.makeText(MainActivity.this, "Server connection failed", Toast.LENGTH_LONG).show();
            return;
        }
        int jsonResult = returnParsedJsonObject(result);
        if(jsonResult == 0){
            pDialog.dismiss();
            Toast.makeText(MainActivity.this, "Invalid username or password", Toast.LENGTH_LONG).show();
            return;
        }
//When the login is Correct
//get_phone and get_id are always null (first problem)
        if(jsonResult == 1){
            SharedPreferences Preferences = getSharedPreferences("MYPREFERNCES", MODE_PRIVATE);
            SharedPreferences.Editor editor = Preferences.edit();
            editor.putBoolean("loggin", checkres);
            editor.putString("SAVED_USERNAME", enteredUsername);
            editor.putString("SAVED_PHONE", get_phone);
            editor.putString("SAVED_ID",get_id );
            editor.apply();

            Intent intent = new Intent(MainActivity.this, LoginActivity.class);
            intent.putExtra("USERNAME", enteredUsername);
            intent.putExtra("MESSAGE", "You have been successfully login to Direct");
            startActivity(intent);
            finish();
        }
    }
    private StringBuilder inputStreamToString(InputStream is) {
        String rLine = "";
        StringBuilder answer = new StringBuilder();
        BufferedReader br = new BufferedReader(new InputStreamReader(is));
        try {
            while ((rLine = br.readLine()) != null) {
                answer.append(rLine);
            }
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        return answer;
    }
}
//getting Json result
private int returnParsedJsonObject(String result){

    JSONObject resultObject = null;
    int returnedResult = 0;
    try {
        resultObject = new JSONObject(result);
        returnedResult = resultObject.getInt("success");
         get_phone = resultObject.getString("phonenum");
         get_id = resultObject.getString("id");
    } catch (JSONException e) {
        e.printStackTrace();
    }
    return returnedResult;
}

以下是Android App点击的PHP文件..

<?php
require_once 'include/user.php';

$username = "";
$password = "";
$email = "";


if(isset($_POST['username'])){
$username = $_POST['username'];
}
if(isset($_POST['password'])){
$password = $_POST['password'];
}
if(isset($_POST['email'])){
$email = $_POST['email'];
}

// Instance of a User class
$userObject = new User();
//Functions..
// Registration of new user
if(!empty($username) && !empty($password) && !empty($email)){
$hashed_password = md5($password);
$json_registration = $userObject->createNewRegisterUser($username,         $hashed_password, $email);

echo json_encode($json_registration);
}

// User Login
if(!empty($username) && !empty($password) && empty($email)){
$hashed_password = md5($password);  
$json_array = $userObject->loginUsers($username, $hashed_password);

echo json_encode($json_array);
}

 // getting data >> here I sent the ID to the database via $username but it is 'INT'
if(!empty($username) && empty($password) && empty($email)){
$json_array = $userObject->getdata($username);

echo json_encode($json_array);
}


?>

以下是被称为的课程。

private $db;
private $db_table = "users";
    private $result1 = "";
    private $result2 = "";

public function __construct(){
    $this->db = new DbConnect();
}

public function isLoginExist($username, $password){     

    $query1 = "SELECT `id` FROM users WHERE username = '$username' AND password = '$password' Limit 1";
    $result1 = mysqli_query($this->db->getDb(), $query1);

    if(mysqli_num_rows($result1) > 0){

             $query2 = "SELECT `email` FROM users WHERE username = '$username' Limit 1";
             $result2 = mysqli_query($this->db->getDb(),$query2);
        mysqli_close($this->db->getDb());
        return true;
    }       
    mysqli_close($this->db->getDb());
    return false;       
}

public function isIDExist($username){   

            $query1 = "SELECT `username` FROM users WHERE 'id' = '$username' Limit 1";
            $result1 = mysqli_query($this->db->getDb(),$query1);

    if(mysqli_num_rows($result1) > 0){
                    $query2 = "SELECT `email` FROM `users` WHERE `id` = '$username' Limit 1";
                    $result2 = mysqli_query($this->db->getDb(),$query2);
        mysqli_close($this->db->getDb());
        return true;
    }       
    mysqli_close($this->db->getDb());
    return false;       
}


public function createNewRegisterUser($username, $password, $email){
    $json = array();
    $query = "insert into users (username, password, email) values ('$username', '$password', '$email')";  
    $inserted = mysqli_query($this->db->getDb(), $query);

    if($inserted == 1){
                    $query1 = "SELECT `id` FROM `users` WHERE `username` = '$username' Limit 1"; 
                    $result1 = mysqli_query($this->db->getDb(), $query1);
        $json['success'] = 1;   
                    $json['id'] = $result1;

}else{
        $json['success'] = 0;
                    $json['id'] = "";
    }
    mysqli_close($this->db->getDb());
    return $json;
}


public function getdata($username){     
$json = array();
    $isitexists = $this->isIDExist($username);
    if($isitexists){
                    $json['success'] = 1;
        $json['username'] = $result1;
                    $json['phonenum'] = $result2;

    }else{
        $json['success'] = 0;
                    $json['username'] = "";
                    $json['phonenum'] = "";

    }
    return $json;           

}





public function loginUsers($username, $password){

    $json = array();
    $canUserLogin = $this->isLoginExist($username, $password);
    if($canUserLogin){
        $json['success'] = 1;
                    $json['id'] = $result1;
                    $json['phonenum'] = $result2;
    }else{
        $json['success'] = 0;
                    $json['id'] = "";
                    $json['phonenum'] = "";
    }
    return $json;
}

}


?>

Answer 1

尝试类似的代码.. if（isset（$ inserted））

for Source_Index in Data'Last .. Data'First loop

PHP始终返回null值

1 个答案: