Question

我正在尝试从users表中获取行，并将其与Articles表连接，其中articles.user_id = users.id和articles.view最多。

public function scopeMostViewedArticle($query)
{
    $query->leftjoin('articles as a', function ($join) {

            $join->on('a.user_id','=','users.id')
                  ->where('a.publish_date', '<',date('Y-m-d H:m'))
                  ->where('a.view','=',?);


            })
        ->groupby('users.id')
        ->orderby('users.id')
        ->select('users.*','a.title as article_title','a.image as article_image');  


}

我对' - ＆gt; where（'a.view'，'='，？）;'有疑问部分。我感谢您的帮助！：）

Answer 1

public function scopeMostViewedArticle($query)
{
    $query->leftjoin('articles as a', function ($join) {

            $join->on('a.user_id','=','users.id')
                  ->where('a.publish_date', '<',date('Y-m-d H:m'))
                  ->max('a.view');   
            })
        ->groupby('users.id')
        ->orderby('users.id')
        ->select('users.*','a.title as article_title','a.image as article_image');  

}

您可以找到更多信息 http://laravel.com/docs/5.1/queries

Laravel 5 eloquent join基于字段最大值

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