Question

我正在尝试从字符串中获取所有出现的内容（带有cbrackets的cbrackets中的文本）。

我试着这样做：

            String DATA = "ctrl_interface=/data/misc/wifi/sockets\n" +
                    "driver_param=use_p2p_group_interface=1\n" +
                    "update_config=1\n" +
                    "device_name=P580_ROW\n" +
                    "manufacturer=LENOVO\n" +
                    "model_name=Lenovo \n" +
                    "model_number=Lenov\n" +
                    "serial_number=hjhjh7\n" +
                    "device_type=10-0050F204-5\n" +
                    "os_version=01020300\n" +
                    "config_methods=physical_display virtual_push_button\n" +
                    "p2p_no_group_iface=1\n" +
                    "\n" +
                    "network={\n" +
                    "    ssid=\"test1\"\n" +
                    "    psk=\"154695\"\n" +
                    "    key_mgmt=WPA-PSK\n" +
                    "    sim_slot=\"-1\"\n" +
                    "    imsi=\"none\"\n" +
                    "    priority=1\n" +
                    "}\n" +
                    "\n" +
                    "network={\n" +
                    "    ssid=\"test1\"\n" +
                    "    psk=\"154695\"\n" +
                    "    key_mgmt=WPA-PSK\n" +
                    "    sim_slot=\"-1\"\n" +
                    "    imsi=\"none\"\n" +
                    "    priority=1\n" +
                    "}\n" +
                    "\n" +
                    "network={\n" +
                    "    ssid=\"test1\"\n" +
                    "    psk=\"154695\"\n" +
                    "    key_mgmt=WPA-PSK\n" +
                    "    sim_slot=\"-1\"\n" +
                    "    imsi=\"none\"\n" +
                    "    priority=1\n" +
                    "}\n" +
                    "\n" +
                    "network={\n" +
                    "    ssid=\"test1\"\n" +
                    "    psk=\"154695\"\n" +
                    "    key_mgmt=WPA-PSK\n" +
                    "    sim_slot=\"-1\"\n" +
                    "    imsi=\"none\"\n" +
                    "    priority=1\n" +
                    "}\n" +
                    "\n" +
                    "network={\n" +
                    "    ssid=\"SSID2\"\n" +
                    "    psk=\"test123456\"\n" +
                    "    key_mgmt=WPA-PSK\n" +
                    "    sim_slot=\"-1\"\n" +
                    "    imsi=\"none\"\n" +
                    "    priority=19\n" +
                    "}";

            String re1=".*?";   // Non-greedy match on filler
            String re2="(\\{.*?\\})";   // Curly Braces 1
            List<String> allMatches = new ArrayList<String>();
            Pattern p = Pattern.compile(re1 + re2, Pattern.CASE_INSENSITIVE | Pattern.DOTALL);
            Matcher m = p.matcher(DATA);


            while (m.find()) {
                allMatches.add(m.group());
            }

            for(int i = 0; i < allMatches.size(); i++) {
                Logger.d(allMatches.get(i).toString());
            }

但首先发现的结果包含不需要的字符：

使用“network =”字符串返回下次发现的出现次数。

如何才能提高我的正则表达式才能只显示格式？：

{whole content in cbracket}

非常感谢任何建议

Answer 1

如果你只需要获得大括号和内部的内容，你可以试试这个：

//                           | escaped opening bracket
//                           |  | any character, 0+ times
//                           |  |   | closing bracket
//                           |  |   |   | dot will also match new lines
Pattern p = Pattern.compile("\\{.*?}", Pattern.DOTALL);
Matcher m = p.matcher(DATA);
while (m.find()) {
    System.out.println(m.group());
}

根据您的输入，它将打印：

{
    ssid="test1"
    psk="154695"
    key_mgmt=WPA-PSK
    sim_slot="-1"
    imsi="none"
    priority=1
}
{
    ssid="SSID2"
    psk="test123456"
    key_mgmt=WPA-PSK
    sim_slot="-1"
    imsi="none"
    priority=19
}

备注

我在这里所做的基本上就是删除Pattern的第一部分，这部分符合＆＃34;不需要的＆＃34;文本。

如果您有更复杂的输入，即大括号内的花括号或大括号的嵌套级别，则会失败（事实上，正则表达式不会是解决方案）。

Java Regex - 如何在字符串中获取cbrackets中的所有内容？

1 个答案: