Question

我有一个带商店运营时间的变量：

t = '08:00-17:00'

现在，我需要检查商店现在是否已打开：

from time import gmtime, strftime
print strftime("%H:%M", gmtime())
#11:26

最合适的方法是什么？作为旁注，我可以在几分钟内获得t，或更方便的东西。

Answer 1

而不是尝试将当前时间转换为字符串，而是应该str.split()将t分成两个不同的时间，然后使用datetime.datetime.time将它们转换为datetime.datetime.strptime()个对象，然后将其与datetime.datetime.now()上的时间组件进行比较。示例 -

import datetime
t = '08:00-17:00'
times = t.split('-')
start_time = datetime.datetime.strptime(times[0],'%H:%M').time()
end_time = datetime.datetime.strptime(times[1],'%H:%M').time()
if start_time <= datetime.datetime.now().time() <= end_time:
    #Do you logic

演示 -

关闭时间 -

>>> import datetime
>>> t = '08:00-17:00'
>>> times = t.split('-')
>>> start_time = datetime.datetime.strptime(times[0],'%H:%M').time()
>>> end_time = datetime.datetime.strptime(times[1],'%H:%M').time()
>>> if start_time <= datetime.datetime.now().time() < end_time:
...         print("Shop open")
... 
>>>

开放时间 -

>>> t = '08:00-18:00'
>>> times = t.split('-')
>>> start_time = datetime.datetime.strptime(times[0],'%H:%M').time()
>>> end_time = datetime.datetime.strptime(times[1],'%H:%M').time()
>>> if start_time <= datetime.datetime.now().time() < end_time:
...         print("Shop open")
...
Shop open
>>>

使用此方法即使支持分钟，您也可以更改用于将time转换为time对象的格式，如果您愿意，还可以支持高达微秒。

Answer 2

首先，您需要将 t 转换为可比较的值，例如整数，所以：

storeOpen, storeCloses = '08h00-17h00'.split('-')

这会将字符串'08h00-17h00'拆分为：

storeOpen => '08h00'
storeCloses => '17h00'

之后，您应该将 storeOpen 和 storeCloses 转换为整数：

storeOpenHour, storeOpenMinutes = storeOpen.split('h') #splits the storeOpen into two
#converts to integer
storeOpenHour = int(storeOpenHour)
storeOpenMinutes = int(storeOpenMinutes)
#you should repeat the same process to storeClose

然后你只是比较它们：

if (nowMinutes > storeOpenMinutes and nowHour > storeOpenHour) and (nowMinutes < storeCloseMinutes and nowHour < storeCloseHour):
    println "is open!"

检查python列表中当前当前小时是否可用

2 个答案: