我在doctrine中遇到了一个问题,我最近开始使用Symfony继续在Symfony中继续一个旧项目,现在我想学习它。 我开始从db解释,我只写了我感兴趣的字段:
用户(ID,姓名,柏)
user_reference(id,id_user [FOREIGN KEY id FROM user],id_user_referenced [FOREIGN KEY id FROM user])
这是查询:
$id_user = $user->getId();
$query = $em->createQueryBuilder()
->select('ur','uu')
->from('DtEcBundle:UserReferences', 'ur')
->innerJoin("ur.id_user","uu")
->where("ur.id_user = :id_user")
->setParameter("id_user",$id_user)
->getQuery();
$userpyramid = $query->getResult();
我在我的twig文件id_user_referenced中打印,但我也会打印"名称,姓氏和路径"来自USER表
对于Entity UserReferences中的print id_user_referenced,有以下代码:
/**
* Set id_user_referenced
*
* @param \Dt\EcBundle\Entity\User $idUserReferenced
* @return UserReferences
*/
public function setIdUserReferenced(\Dt\EcBundle\Entity\User $idUserReferenced = null) {
$this->id_user_referenced = $idUserReferenced;
return $this;
}
/**
* Get id_user_referenced
*
* @return \Dt\EcBundle\Entity\User
*/
public function getIdUserReferenced() {
return $this->id_user_referenced;
}
使用以下内容将实体用户中的id(如id)转换为字符串:
public function __toString(){
return strval($this->id);
}
现在,如果我在select this中添加我的查询:
->select('ur','uu.path')
Symfony发给我一个错误:
Key" idUserReferenced"对于带有键的数组" 0,path"在...中不存在 DtEcBundle:Profilo:第40行的digitalpr-profile.html.twig
为什么?我怎么能解决它?
UserReferences.php
namespace Dt\EcBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* UserReferences
*
* @ORM\Table(name="user_references" ,uniqueConstraints= {@ORM\UniqueConstraint(name="recension_unique", columns={"id_user", "id_user_referenced"})})
* @ORM\Entity(repositoryClass="Dt\EcBundle\Entity\UserReferencesRepository")
*/ class UserReferences {
/**
* @var integer
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
*
* @var Dt\EcBundle\Entity\User
* @ORM\ManyToOne(targetEntity="Dt\EcBundle\Entity\User", inversedBy="references")
* @ORM\JoinColumn(name="id_user", referencedColumnName="id")
*/
private $id_user;
/**
* @ORM\ManyToOne(targetEntity="Dt\EcBundle\Entity\User")
* @ORM\JoinColumn(name="id_user_referenced", referencedColumnName="id")
* */
private $id_user_referenced;
/**
*
* @var string
* @ORM\Column(name="reference", type="text", nullable=false,unique=false);
*/
private $reference;
/**
* Get id
*
* @return integer
*/
public function getId() {
return $this->id;
}
/**
* Set reference
*
* @param string $reference
* @return UserReferences
*/
public function setReference($reference) {
$this->reference = $reference;
return $this;
}
/**
* Get reference
*
* @return string
*/
public function getReference() {
return $this->reference;
}
/**
* Set id_user
*
* @param \Dt\EcBundle\Entity\User $idUser
* @return UserReferences
*/
public function setIdUser(\Dt\EcBundle\Entity\User $idUser = null) {
$this->id_user = $idUser;
return $this;
}
/**
* Get id_user
*
* @return \Dt\EcBundle\Entity\User
*/
public function getIdUser() {
return $this->id_user;
}
/**
* Set id_user_referenced
*
* @param \Dt\EcBundle\Entity\User $idUserReferenced
* @return UserReferences
*/
public function setIdUserReferenced(\Dt\EcBundle\Entity\User $idUserReferenced = null) {
$this->id_user_referenced = $idUserReferenced;
return $this;
}
/**
* Get id_user_referenced
*
* @return \Dt\EcBundle\Entity\User
*/
public function getIdUserReferenced() {
return $this->id_user_referenced;
}
}
user.php的
/**
* @var integer
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
* @var string
*
* @ORM\Column(name="name", type="string", length=255, unique=false, nullable=false)
* @Assert\NotBlank(message="user.name.not.blank")
* @Assert\Length(
* min=2,
* max=150,
* minMessage="user.name.not.min",
* maxMessage="user.name.not.max" )
*/
protected $name;
/**
* @var string
*
* @ORM\Column(name="surname", type="string", length=255, unique=false, nullable=false)
* @Assert\NotBlank(message="user.surname.not.blank")
* @Assert\Length(
* min=2,
* max=150,
* minMessage="user.surname.not.min",
* maxMessage="user.surname.not.max" )
*/
protected $surname;
/**
* @var \DateTime
* @ORM\Column(name="borndate", type="datetime",unique=false,nullable=false)
*/
protected $borndate;
/**
*
* @var string
* @ORM\Column(name="tel", type="string",length=50, unique=true,nullable=true)
* @Assert\Regex("/[0-9]/")
*/
protected $tel;
/**
*
* @var string
* @ORM\Column(name="city", type="string",length=255,unique=false,nullable=true)
* @Assert\NotBlank(message="user.expert.city.not.blank",groups={"Expert"})
* @Assert\NotBlank(message="user.expert.city.not.blank",groups={"ExpertProfile"})
* @Assert\Length(
* min=2,
* max=150,
* minMessage="user.expert.city.not.min",
* maxMessage="user.expert.city.not.max", groups={"Expert"} )
* @Assert\Length(
* min=2,
* max=150,
* minMessage="user.expert.city.not.min",
* maxMessage="user.expert.city.not.max", groups={"ExpertProfile"} )
*/
protected $city;
/**
*
* @var string
* @ORM\Column(name="street", type="string",length=255,unique=false,nullable=true)
* @Assert\NotBlank(message="user.expert.street.not.blank",groups={"Expert"})
* @Assert\NotBlank(message="user.expert.street.not.blank",groups={"ExpertProfile"})
* @Assert\Length(
* min=2,
* max=150,
* minMessage="user.expert.street.not.min",
* maxMessage="user.expert.street.not.max", groups={"Expert"} )
* @Assert\Length(
* min=2,
* max=150,
* minMessage="user.expert.street.not.min",
* maxMessage="user.expert.street.not.max", groups={"ExpertProfile"} )
*/
protected $street;
/**
*
* @var type
*
* @Assert\File(
* maxSize = "1024k",
* mimeTypes = {"image/gif","image/jpeg","image/pjpeg","image/png"},
* mimeTypesMessage = "user.image.mimetypes",
* maxSizeMessage = "user.image.maxsize"
* )
* @Assert\NotBlank(message="user.expert.mandatory.photo",groups={"Expert"})
*
*/
protected $photo;
/**
* @ORM\Column(name="photo_path",type="string", length=255, nullable=true,unique=true)
*/
protected $path;
/**
* Membri per la gestione dei file
*
*/
答案 0 :(得分:1)
问题在于,学说会在Array Hydration模式下保持您的结果,而您期望Object Hydraion。
在第一种情况下,您要求提供2个相关对象,并且学说可以链接它们。在第二个中你要求一个对象和一个标量值,并且教义不能链接它们,所以它将它们返回到结果数组的两个单独的字段中。
所以你在select('ur','uu.path')
的情况下从$ query-> getResult()获得的结果不是User对象的数组,而是一个包含2个字段的数组 - $ result [0]所有找到的用户对象,以及uu.path的$ result [' path'] - 因为uu.path是标量值而不是对象。
因此,您需要制作select('ur','uu')
并将结果视为$result->getIdUserReferenced()->getPath()
。
或者(如果你想节省一些资源,但我认为不值得),请制作select('ur','uu.path')
然后制作var_dump结果。你会看到如何满足你的需求。
答案 1 :(得分:0)
我尝试这种模式,但不是很好
$id_user = $user->getId();
$query = $em->createQueryBuilder()
->select('ur','uu')
->from('DtEcBundle:UserReferences', 'ur')
->innerJoin("ur.id_user","uu")
->where("ur.id_user = :id_user")
->setParameter("id_user",$id_user)
->getQuery();
$userpyramid = $query->getResult();
$form = $this->get('form.factory')->createNamedBuilder('form', 'form')
->setMethod('POST')
->setAction($this->generateUrl('profilo_secondlevel'))
->add('save', 'submit', ['label' => 'Prova'])
->getForm();*/
$result->getIdUserReferenced()->getPath();
return $this->render('DtEcBundle:Profilo:index.html.twig', array(
'user' => $user,
'tags' => $tags,
'followers' =>$followers,
'expert' =>$expert,
'user_expert' =>$user_expert,
'well_cat' =>$well_cat,
'user_notification' => $user_notifications,
"udputenti" => $udputenti,
"userpyramid" => $userpyramid,
"result"=> $result
//'form'=>$form->createView()
));`