Question

daviderossi.blogspot.com提供了一些帮助，我设法让一些代码用另一个替换xml值

def fm_xml = '''<?xml version="1.0" encoding="UTF-8"?>
<MAlong>
<Enquiry.ID>SC11147</Enquiry.ID>
<student.name_middle></student.name_middle>
<student.name_known></student.name_known>
<student.name_previous></student.name_previous>
<student.name_cert>John REnfrew</student.name_cert>
<student.detail_gender>M</student.detail_gender>
<student.sign_name>John Renfrew</student.sign_name>
<student.sign_date>05/01/2010</student.sign_date>
</MAlong>'''

xml = new XmlParser().parseText(fm_xml)
ix = xml.children().findIndexOf{it.name() =='student.name_middle'}
nn = new Node(xml, 'student.name_middle', "NEW")
if (ix != -1 ) {
xml.children()[ix] = nn
nn.parent = xml
}
writer = new StringWriter()
new XmlNodePrinter(new PrintWriter(writer)).print(xml)
result = writer.toString()

这给了我以下输出但是我希望它与正确形成的结束标记一起，否则对新数据的XPath查询将失败..

所以例如

<student.name_known/>

需要成为

<student.name_known></student.name_known>

任何想法??

<MAlong>
<Enquiry.ID>
 SC11147
</Enquiry.ID>
<student.name_middle>
 NEW
</student.name_middle>
<student.name_known/>
<student.name_previous/>
<student.name_cert>
 John REnfrew
</student.name_cert>
<student.detail_gender>
 M
</student.detail_gender>
<student.sign_name>
 John Renfrew
</student.sign_name>
<student.sign_date>
 05/01/2010
</student.sign_date>
<student.name_middle>
 NEW
</student.name_middle>
</MAlong>

Answer 1

<student.name_known/>

完美的格式化，并且XPath查询应该在此XML结构上运行良好。

Answer 2

它应该通过将 expandEmptyElements 选项设置为true来实现

请参阅http://groovy.codehaus.org/api/groovy/util/XmlNodePrinter.html#setExpandEmptyElements%28boolean%29

Groovy xml解析然后重建

2 个答案: