我只是想询问你关于我的表查询的帮助，每次点击按钮时，都会显示一个新表。而不是只有一行将更新到表，后面的整个表显示是旧表。请帮我查一下我的代码。谢谢
demo.insert.php
$dbHost = 'localhost'; // usually localhost
$dbUsername = 'root';
$dbPassword = 'thartpc';
$dbDatabase = 'hospital';
$db = mysql_connect($dbHost, $dbUsername, $dbPassword) or die ("Unable to connect to Database Server.");
mysql_select_db ($dbDatabase, $db) or die ("Could not select database.");
$sql_check = mysql_query("SELECT * FROM messages order by med_id desc");
if(isSet($_POST['content2'])){
$content2=$_POST['content2'];
$content3=$_POST['content3'];
mysql_query("insert into messages(medname, quantity) values ('$content2','$content3')");
$sql_in= mysql_query("SELECT * FROM messages order by med_id desc");
$r=mysql_fetch_array($sql_in);
}
?>
<?php
require_once 'config.php';
$query = mysql_query("SELECT * FROM messages order by med_id desc") or die ("could not search");
$count = mysql_num_rows($query);
?>
<div class="container">
<div class="panel panel-info">
<div class="panel-heading" class="panel-title">
<h7>Name</h7>
</div>
<div class="panel-body" style="padding-top:30px">
<?php
echo "
<table class='table table-hover';>
<tr>
<td style='border:1px solid; color:gray' align='center'> ID</td>
<td style='border:1px solid; color:gray' align='center'>Name</td>
<td style='border:1px solid; color:gray' align='center'>Quantity</td>
</tr>";
while($row = mysql_fetch_array($query)){
echo "
<tr>
<td style='border:1px solid; color:gray' align='center'>".$row['med_id']." </td>
<td style='border:1px solid; color:gray' align='center'>".$row['medname']." </td>
<td style='border:1px solid; color:gray' align='center'>".$row['quantity']."</td>
</tr> ";
}
echo " </table>";
?>
</div>
</div>
</div>
inserting.php
<?php
session_start();
if(isset($_POST['search'])){
$globalpid = $_POST['search'];
$_SESSION['search'] = "$globalpid";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap.min.css">
<link rel="stylesheet" type="text/css" href="css/custom.css">
<!-- Optional theme -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap- theme.min.css">
<title>Insert Record with jQuery and Ajax</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js"></script>
<script type="text/javascript">
$(function(){
$("#v").click(function(){
var element = $(this);
var test2 = $("#content2").val();
var test3 = $("#content3").val();
var dataString = 'content2='+ test2+'&content3='+ test3;
if(test2==''){
alert("Please Enter Some Text");
}else{
$("#flash").show();
$("#flash").fadeIn(400).html('<img src="http://tiggin.com/ajax-loader.gif" align="absmiddle"> <span class="loading">Loading Comment...</span>');
$.ajax({
type: "POST",
url: "demo_insert.php",
data: dataString,
cache: false,
success: function(html){
$("#display").after(html);
document.getElementById('content2').value='';
$("#flash").hide();
}
});
}
return false;
});
});
</script>
</head>
<body>
<?php
require_once 'pharmacyheader.php';
require_once 'pharmacysearch.php';
require_once 'patientquery.php';
?>
<div class="container">
<form method="post" name="form" action="">
<div class="col-md-6">
<div class="panel panel-info">
<div class="panel-heading"><h7>Name A - F</h7></div>
<div class="panel-body">
<select class="form-control" id="content2" name="content2">
<option id="0" style="width:100px"></option>
<?php
require_once 'config.php';
$medicine = mysql_query("SELECT * FROM medicine");
while ($row = mysql_fetch_array($medicine)) {
echo '<option id="' . $row['medicinename'] . '"';
echo ' value="' . $row['medicinename'] . '"';
if($row['brandid'] == $row['medicinename']) {
echo ' selected="selected"';
}
echo '>';
echo $row['medicinename'];
echo '</option>';
}
?>
</select>
</div>
</div>
</div>
<div class="col-md-6">
<div class="panel panel-info">
<div class="panel-heading"><h7>Quantity</h7></div>
<div class="panel-body">
<select class="form-control" id="content3" name="content3">
<option id="0" style="width:100px"></option>
<?php
require_once 'config.php';
$quantity = mysql_query("SELECT * FROM quantity");
while ($row = mysql_fetch_array($quantity)) {
echo '<option id="' . $row['quantityname'] . '"';
echo ' value="' . $row['quantityname'] . '"';
if($row['quantityid'] == $row['quantityname']) {
echo ' selected="selected"';
}
echo '>';
echo $row['quantityname'];
echo '</option>';
}
?>
</select>
</div>
</div>
</div>
<div class="row"><br />
<div class="col-md-1">
<input type="submit" value="Add" id="v" name="submit" class="form-control" />
</div>
</div>
</form>
</div>
<div style="height:7px"></div>
<div id="flash" align="left" ></div>
<div id="display" align="left"></div>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.2.0/js/bootstrap.min.js"> </script>
<script src="typeahead.min.js"></script>
<script src="http://code.jquery.com/jquery-2.1.1.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.2.0/js/bootstrap.min.js"> </script>
<script src="js/bootstrap.min.js"></script>
<script src="js/jquery.min.js"></script>
<script type="text/javascript" src="jquery.min.js"></script>
</body>
</html>
答案 0 :(得分：0)
请看下面的代码，
echo "<table class='table table-hover';>
<tr>
<td style='border:1px solid; color:gray' align='center'> ID</td>
<td style='border:1px solid; color:gray' align='center'>Name</td>
<td style='border:1px solid; color:gray' align='center'>Quantity</td>
</tr>";
while($row = mysql_fetch_array($query))
{
echo "
<tr>
<td style='border:1px solid; color:gray' align='center'>".$row['med_id']." </td>
<td style='border:1px solid; color:gray' align='center'>".$row['medname']." </td>
<td style='border:1px solid; color:gray' align='center'>".$row['quantity']."</td>
</tr> ";
}
echo "</table>";
我认为每次调用ajax时都会执行此代码。
黄油解决方案是放在＆＃34; table＆＃34;标记你进行ajax调用的地方，只附加来自ajax响应的tr内容。
这可能会帮助你。
如果您有任何疑问，请告诉我
由于
答案 1 :(得分：0)
好的，所以在查看代码时我可以看到：
您使用ajax检索包含内容的表
你有一个.display元素应该接收ajax数据
因此，每次调用.ajax时，都会收到一个新的完整表格（请查看demo_insert.php）。将新内容放入＆＃34; .display＆＃34; item，你使用jquery＆＃34; .after＆＃34; （你应该检查它是如何工作的[{3}}）
.after应该在其他东西之后添加一些东西。因此，合乎逻辑的是，你的ajax返回（完整的表格）是在＆＃34; .display＆＃34;之后添加的。因为你要求jquery这样做。
你应该做的只是更换你的＆＃34; .display＆＃34;内容与.ajax响应...
$('#display').html(html);
，或类似的东西......