PHP如何保存cookie / sessions的值

时间:2015-09-25 05:24:30

标签: php session cookies

我正在使用PHP制作一个简单的游戏。

我需要存储某些内容,例如游戏的轮次以及总数等等,并保存这些数据并稍后访问它(在另一页或我回到此页面时)

我尝试过使用会话,但这对我没用。

我可以使用cookies吗?

这是我第一次使用PHP。

这是我的代码,如果它有助于理解:

<form method="get" action= "skunk.php">
    <h1>PLAY SKUNK</h1>

    ROLL AGAIN? <br> 
    yes<input type="radio" name="role2" value="yes"/>
    no<input type="radio" name="role2" value="no"/>
    <br>
    <input type="submit"/>

    </form>

<?php 

session_start();
    $_SESSION["s"] = array(0);
    $_SESSION["k1"] =array(0);
    $_SESSION["u"] = array(0);
    $_SESSION["n"] = array(0);
    $_SESSION["k2"] = array(0);
    $rand = 0;
    $rand2 = 0;
    $_SESSION["round"] = 1;
    if($_REQUEST["role2"] == "yes"){
        $rand = rand (1, 6);
        $rand2 = rand(1, 6);
         if($rand == 1 and $rand ==1){
            switch ($_SESSION["round"]) {
                case 1:
                    $_SESSION["s"] = array(0);
                    break;
                case 2:
                    $_SESSION["s"] = array(0);
                    $_SESSION["k1"] =array(0);
                    break;
                case 3:
                    $_SESSION["s"] = array(0);
                    $_SESSION["k1"] =array(0);
                    $_SESSION["u"] = array(0);
                    break;
                case 4:
                    $_SESSION["s"] = array(0);
                    $_SESSION["k1"] =array(0);
                    $_SESSION["u"] = array(0);
                    $_SESSION["n"] = array(0);
                    break;
                case 5:
                    $_SESSION["s"] = array(0);
                    $_SESSION["k1"] =array(0);
                    $_SESSION["u"] = array(0);
                    $_SESSION["n"] = array(0);
                    $_SESSION["k2"] = array(0); 
                    break;
            }
         }
         if($rand > 1 and $rand2 > 1) {
            switch ($_SESSION["round"]) {
                case 1:
                    array_push($_SESSION["s"], $rand, $rand2);
                    break;
                case 2:
                    array_push($_SESSION["k1"], $rand, $rand2);
                    break;
                case 3:
                    array_push($_SESSION["u"], $rand, $rand2);
                    break;
                case 4:
                    array_push($_SESSION["n"], $rand, $rand2);
                    break;
                case 5:
                    array_push($_SESSION["k2"], $rand, $rand2);
                    break;
            }
            $_SESSION["round"]++;
        }

        if($_SESSION["round"] > 5){
            session_destroy();
        }
        echo "you rolled: " . $rand . "\n";
        echo "you rolled: " . $rand2;

    }

?>
    <table style="width:100%" border="1" >
          <tr>
            <td>S</td>
            <td>K</td> 
            <td>U</td>
            <td>N</td>
            <td>K</td>
          </tr>
    </table>
    <table style="width:100%" border="1" >
          <tr>
            <td><?php echo array_sum($_SESSION["s"]); ?></td>
            <td><?php echo array_sum($_SESSION["k1"]); ?></td> 
            <td><?php echo array_sum($_SESSION["u"]); ?></td>
            <td><?php echo array_sum($_SESSION["n"]); ?></td>
            <td><?php echo array_sum($_SESSION["k2"]); ?></td>
          </tr>
    </table>

1 个答案:

答案 0 :(得分:0)

我会将会话仅用于用户日志状态检查,并将所有其他数据存储到数据库中,这样可以更容易管理并更加一致。