因此,在存钱罐类中,我有四个变量:pennies
,nickels
,dimes
和quarters
。如果我的用户输入三个nickels
,我想将其转换为1个dime
和1个nickel
。我知道这是一个简单的问题,但我现在只是愚蠢。这是我现有的:
public void optimize() { //This whole method is 100% terrible.
nickels = nickels + pennies/5;
pennies -= (nickels*5);
quarters = quarters + nickels/5;
nickels -= (quarters*5);
dimes = dimes + nickels/2;
nickels -= (dimes*2);
}
答案 0 :(得分:3)
public void optimize() {
int total = (25 * quarters) + (10 * dimes) + (5 * nickels) + pennies
quarters = (total/25); //note the integer division
total = total % 25; //no more quarters, cut off 25 until we're less than 25
dimes = (total/10);
total = total % 10;
nickels = (total/5);
total = total % 5;
pennies = total;
}
似乎某些事情应该有效。