Question

我试图编写一个代码来查找文件中的特定文本并获取该行。

f = open('programa.txt','r') 
for line in f:
    if (line == "[Height of the board]\n"):
      ## skip to next line and saves its content

    print(line)

Answer 1

设置一个标志，以便你知道如何抓住下一行。

f = open('programa.txt','r') 
grab_next = False
for line in f:
    if grab_next:
        print(line)
    grab_next = line == "[Height of the board]\n"

Answer 2

文件对象是Python中的迭代器;当for循环隐式使用迭代器协议时，您可以在需要跳过时自己手动调用它：

with open('programa.txt') as f:
    for line in f:
        if line == "[Height of the board]\n":
            # skip to next line and saves its content
            line = next(f)
        print(line)

存储下一行的示例代码不清楚，因此我将其存储回line，使原始行标题消失。如果目标是仅打印该行并中断，则可以使用：

with open('programa.txt') as f:
    for line in f:
        if line == "[Height of the board]\n":
            # skip to next line and saves its content
            importantline = next(f)
            print(importantline)
            break

Answer 3

当你回顾而不是试图向前看时，这样的问题几乎总是更简单。毕竟，找出最后一行是微不足道的;你只需将它存储在变量中！在这种情况下，如果上一个行是标题，则要保存当前行：

access

如何在python中的列表中迭代时跳转到下一个元素？

3 个答案: